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27 Jan 2008, 14:40
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Please see attached.
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27 Jan 2008, 15:02
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Review Statement 1:
If angle ABD is 60 degs, then angle BAD must be 30 degs. In a 30-60-90 right triangle, the sides are in the ratio 1:sqrt(3):2
Therefore in triangle ABD, the sides must be 6, 6.sqrt(3), and 12.
Review Statement 2:
AC=12, and AB=12 (from 1), which means angle ABD and angle ACD must also be equal. So triangle ABC must be an equilateral triangle and BC must also = 12.
From 1 and 2, we can find the area of the triangle as being 1/2 times the base times the altitude. So 1/2 x 12 x 6.sqrt(3)
Therefore, C.
If angle ABD is 60 degs, then angle BAD must be 30 degs. In a 30-60-90 right triangle, the sides are in the ratio 1:sqrt(3):2
Therefore in triangle ABD, the sides must be 6, 6.sqrt(3), and 12.
Review Statement 2:
AC=12, and AB=12 (from 1), which means angle ABD and angle ACD must also be equal. So triangle ABC must be an equilateral triangle and BC must also = 12.
From 1 and 2, we can find the area of the triangle as being 1/2 times the base times the altitude. So 1/2 x 12 x 6.sqrt(3)
Therefore, C.
27 Jan 2008, 17:30
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A = 1/2 (b) (sqroot3)
Agree with C. Statement 1 tells us 30-60-90 triangle. With this we can find BD, but not DC. We cannot assume that they are equal.
Statement 2 allows us to calculate DC.
Together we know BD+DC = base. We can now calculate the area.
Agree with C. Statement 1 tells us 30-60-90 triangle. With this we can find BD, but not DC. We cannot assume that they are equal.
Statement 2 allows us to calculate DC.
Together we know BD+DC = base. We can now calculate the area.
