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# Arithmetic

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Intern
Joined: 11 Jul 2009
Posts: 15

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12 Jul 2009, 06:58
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in certain pegboard, each row of holes other than the bottom one contains exactly one more hole than the row below it. if there are 4 rows in all and 26 holes in the pegboard, how many holes are in bottom row?
1)4 2) 5 3) 6 4)7 5)8

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Intern
Joined: 12 Jul 2009
Posts: 7
Location: Delhi

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12 Jul 2009, 09:40
Ans would be 2) 5..

Let's consider the bottom row has x holes..
So , x + (x + 1) + (x + 2) + (x + 3) = 26
.. , 4x + 6 = 26
So , x = 5
Intern
Joined: 11 Jul 2009
Posts: 15

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12 Jul 2009, 14:31
yep right. I went by backsolving by starting with 6 first. i.e 6+7+8+9 =30. So opted for 5. now its 5+6+7+8=26 holes & 4 rows
Intern
Joined: 05 Sep 2006
Posts: 14

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13 Jul 2009, 12:13
Manager
Joined: 16 Apr 2009
Posts: 219
Schools: Ross

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13 Jul 2009, 12:35
Quote:
in certain pegboard, each row of holes other than the bottom one contains exactly one more hole than the row below it. if there are 4 rows in all and 26 holes in the pegboard, how many holes are in bottom row?
1)4 2) 5 3) 6 4)7 5)8

4 rows
3 rows - n+(n+1)+(n+2)
Let x be the no of holes in the bottom row

n+(n+1)+(n+2)+x=26
3n+3+x=26
3n+x=23

23 -3(5 -no of holes)=23-15=8
23 -3(6 -no of holes)=23-18=5

Hence 5

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If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: Arithmetic   [#permalink] 13 Jul 2009, 12:35
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