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arjtryarjtry
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As a part of a game, four people each much secretly chose an 19 Jul 2008, 22:44
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As a part of a game, four people each much secretly chose an integer between 1 and 4 inclusive. What is the approximate likelihood that all four people will chose different numbers?

SORRY , there are no choices,
but is this ok
nos. are 1,2,3,4
1 st person can choose- 1/4( 1 out of 4 nos)
2nd can choose 2/3( 2 out of remaining 3)
3 can choose 1/2( 1 out of remaining 2)
4th only 1
1/4*2/3*1/2*1=1/12.



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durgesh79
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As a part of a game, four people each much secretly chose an 19 Jul 2008, 23:26
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look at it this way .. you have 4 slots, each can take 4 different values... to no of ways = 4^4

first slot can take any number = 4
second slot can take only 3 numbers = 3
third slot can take only 2 numbers = 2
fourth slot can take only remaining number = 1

probability = 4*3*2*1 / 4^4

= 3/32
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arjtryarjtry
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As a part of a game, four people each much secretly chose an 20 Jul 2008, 00:18
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durgesh... i owe u one!!!!thanks..
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durgesh79
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As a part of a game, four people each much secretly chose an 20 Jul 2008, 00:36
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arjtryarjtry
durgesh... i owe u one!!!!thanks..
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you dont have to owe me .. just hit the kudos... and we are even.... :wink:



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