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07 Apr 2021, 05:45
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:50) correct
19%
(01:50)
wrong
based on 31
sessions
History
Date
Time
Result
Not Attempted Yet
As per the previous year data, $y can buy x number of items. If the average cost of each item increased by 20 percent this year, then the number of items can be bought with $3y equals
(A) x
(B) 1.50x
(C) 2.50x
(D) 3x
(E) 3.50x
(A) x
(B) 1.50x
(C) 2.50x
(D) 3x
(E) 3.50x
08 Apr 2021, 23:51
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Bunuel
(I) Substitution
Take x=100 and y=100, so cost of each item is 1$.
The cost per item now becomes z=1.2*1=1.2
Now, you have 3*100$ and cost of each item is 1.2
Number of items that can be purchased = \(\frac{300}{1.2}=250\)
Check the option that gives 250 as the answer after substituting x=100
(II) Method
$y can buy x number of items
So each item costs y/x.
An increase of 20% means 1.2y/x
So for 3y, we will get \(\frac{3y}{\frac{1.2y}{x}}=2.5x\)
(III) Proportion
The rate and number of items are inversely proportional as the amount remains the same.
So if you got x for y and, therefore, 3x for 3y, then an increase of 1.2 in cost will mean a decrease of 1.2 in quantity => \(\frac{3x}{1.2}=2.5x\)
14 Apr 2021, 03:27
Kudos
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Given
To find
Approach and Working out:
Hence, option C is the correct answer.
Correct Answer: Option C
- • As per the previous year data, $y can buy x number of items.
• The average cost of each item increased by 20 percent this year.
To find
- • The number of items can be bought with $3y equals
Approach and Working out:
- • Average cost of each item previous year =\(\frac{ $y}{x}\)
• Average cost of each item this year = \(\frac{$1.2y}{x}\)
• Item that can be bought with $3y = \(\frac{3y }{1.2y /x}\) = \(\frac{3x }{1.2}\) = 2.5x
Hence, option C is the correct answer.
Correct Answer: Option C
