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# As shown in figure, segment AC and segment BD are perpendicular bisect

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As shown in figure, segment AC and segment BD are perpendicular bisect  [#permalink]

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10 Oct 2014, 01:09
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As shown in figure, segment AC and segment BD are perpendicular bisector to each other at point O. If OA = OB = 4, perimeter of the shaded region would be

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A: $$2\pi + 16$$

B: $$3\pi + 24$$

C: $$4\pi + 12$$

D: $$4\pi + 16$$

E: $$4\pi + 20$$
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Joined: 02 Sep 2009
Posts: 64248
Re: As shown in figure, segment AC and segment BD are perpendicular bisect  [#permalink]

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10 Oct 2014, 01:14
PareshGmat wrote:
As shown in figure, segment AC and segment BD are perpendicular bisector to each other at point O. If OA = OB = 4, perimeter of the shaded region would be

A: $$2\pi + 16$$

B: $$3\pi + 24$$

C: $$4\pi + 12$$

D: $$4\pi + 16$$

E: $$4\pi + 20$$

The perimeter equals to half othe circumference of the circle plus two diameters = $$\pi{r}+2d=4\pi+16$$.

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Re: As shown in figure, segment AC and segment BD are perpendicular bisect  [#permalink]

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06 Aug 2019, 23:34
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Re: As shown in figure, segment AC and segment BD are perpendicular bisect   [#permalink] 06 Aug 2019, 23:34

# As shown in figure, segment AC and segment BD are perpendicular bisect

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