1) Brian’s walking speed is twice the difference between Ashok’s walking speed and his own.
B = 2(A-B)
B = 2A -2B
3B = 2A
B = [2A][/3]
R *
T =
DA) R * T = D + 30
B) 2R/3 * T = D
Catch-Up formula => d1 = d2
therefore, RT - 30 = 2RT/3
RT - 2RT/3 = 30
RT/3 = 30
RT = 90
Substitute RT for B -> 2/3 (90) = D ---> D=60
2) If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds.
5A = 3(A+B)
5A = 3A +3B
2A = 3B
B = 2A/3 -> same thing as found in A.