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29 Jan 2018, 05:41
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
63% (01:31) correct
37%
(01:32)
wrong
based on 308
sessions
History
Date
Time
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Not Attempted Yet
At 3 pm, Jennifer went into labor. There is a 70% chance her baby will be born each hour that she is in labor. What is the probability that her baby will be born at 6 pm on the same day?
(A) 0.027
(B) 0.063
(C) 0.147
(D) 0.27
(E) 0.343
(A) 0.027
(B) 0.063
(C) 0.147
(D) 0.27
(E) 0.343
29 Jan 2018, 06:17
Kudos
Bookmarks
Bunuel
If the probability that the baby is born in an hour is 0.7(70%),
then the probability that the baby is not born in that hour is 0.3
If the baby is to born at 6, the baby can't be born at 4 or 5,
but must definitely be born at 6.
The probability that the baby is born at 6 is \(0.3*0.3*0.7 =\) 0.063(Option B)
General Discussion
29 Jan 2018, 07:24
Kudos
Bookmarks
P(Born)= 0.7; P(not born)= 0.3
for the baby to be born at 6 pm, we have
P(not born 4 pm) * P(not born 5 pm) * P(born 6 pm) = 0.3*0.3*0.7 = 0.063
for the baby to be born at 6 pm, we have
P(not born 4 pm) * P(not born 5 pm) * P(born 6 pm) = 0.3*0.3*0.7 = 0.063
