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At a certain bakery, of the cookies sold in one week were chocolate ch

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At a certain bakery, of the cookies sold in one week were chocolate ch [#permalink]

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New post 07 Apr 2017, 11:38
1
5
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

79% (01:43) correct 21% (01:49) wrong based on 91 sessions

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At a certain bakery, 1/4 of the cookies sold in one week were chocolate chip and 1/5 of the remaining cookies sold were oatmeal raisin. If x of the cookies sold were oatmeal raisin, how many were chocolate chip?

A. 1/20(x)
B. 9/20(x)
C. 4/5(x)
D. 5/4(x)
E. 5/3(x)

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Re: At a certain bakery, of the cookies sold in one week were chocolate ch [#permalink]

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New post 07 Apr 2017, 11:53
1
Total = y

CC = \(\frac{1}{4}\)* y
Oatmeal = x

\(\frac{1}{5}\) * \(\frac{3}{4}\)* y = x

y= \(\frac{20}{3}\) * x

\(\frac{1}{4}\) * y = \(\frac{5}{3}\) * x
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At a certain bakery, of the cookies sold in one week were chocolate ch [#permalink]

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New post Updated on: 26 Apr 2017, 13:07
EDITED, many thanks to Nunuboy1994. (Switched variables.)

------------------------------------------------------------------------

Let total cookies = 100. (Choose a number divisible by 4 and 5)

# choc chip = Y
Y = 1/4 of 100 = 25

75 cookies left.
# oatmeal raisin = X
X = 1/5 of 75 = 15

Plug in X = 15, look for answer where Y = 25.

Only E gives Y = 25.
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Originally posted by generis on 11 Apr 2017, 07:25.
Last edited by generis on 26 Apr 2017, 13:07, edited 1 time in total.
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Re: At a certain bakery, of the cookies sold in one week were chocolate ch [#permalink]

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New post 23 Apr 2017, 21:59
1
genxer123 wrote:
Let total cookies=100. (Choose a number divisible by 4 and 5)

# choc chip = x
x = 1/4 of 100 = 25

75 cookies left.
# oatmeal raisin = y
y = 1/5 of 75 = 15

Plug in x = 25, y = 15. Only E gives x = 25.


Shouldn't it be the other way around because 5/3(25) is 5/75 which is 1/15
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Re: At a certain bakery, of the cookies sold in one week were chocolate ch [#permalink]

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New post 26 Apr 2017, 13:08
Nunuboy1994 wrote:
genxer123 wrote:
Let total cookies=100. (Choose a number divisible by 4 and 5)

# choc chip = x
x = 1/4 of 100 = 25

75 cookies left.
# oatmeal raisin = y
y = 1/5 of 75 = 15

Plug in x = 25, y = 15. Only E gives x = 25.


Shouldn't it be the other way around because 5/3(25) is 5/75 which is 1/15


I should have been more careful with variables. When doing the problem, I used variables labeled "CC" and "OR."

I plugged in the right number (i.e., I plugged in what I got for oatmeal raisin in order to get # of chocolate chip cookies in terms of # of oatmeal raisin cookies) and got the right answer, just mislabeled when posting.

Yes, it should be the other way around: for the numbers I chose, plug in x = 15 and look for answer of 25. Edited. Thanks much! :)
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In the depths of winter, I finally learned
that within me there lay an invincible summer.

-- Albert Camus, "Return to Tipasa"

Re: At a certain bakery, of the cookies sold in one week were chocolate ch   [#permalink] 26 Apr 2017, 13:08
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