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At a certain department store presentwrapping counter, each
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Updated on: 20 Oct 2013, 08:56
Question Stats:
46% (02:36) correct 54% (02:38) wrong based on 367 sessions
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At a certain department store presentwrapping counter, each clerk will wrap no fewer than twenty and no more than thirty presents per hour. If seventy people are standing in line, will all of their presents be wrapped after one hour? (1) Each person in line has at least one present to be wrapped by one of the six clerks at the counter. (2) If each person in line had one more present to be wrapped, nine clerks would be required to guarantee that every present would be wrapped in one hour.
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Originally posted by chiragr on 08 Feb 2006, 00:16.
Last edited by Bunuel on 20 Oct 2013, 08:56, edited 1 time in total.
Renamed the topic, edited the question and added the OA.




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Re: At a certain department store presentwrapping counter, each
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20 Oct 2013, 09:21
At a certain department store presentwrapping counter, each clerk will wrap no fewer than twenty and no more than thirty presents per hour. If seventy people are standing in line, will all of their presents be wrapped after one hour?Say each clerk can wrap x presents per hour. We are given that \(20\leq{x}\leq{30}\). (1) Each person in line has at least one present to be wrapped by one of the six clerks at the counter. From that we can get that the number of presents to be wrapped is at least 70 and that there are 6 clerks at the counter. Now, the number of presents 6 clerks can wrap in an hour is \(120\leq{x}\leq{180}\). Still not sufficient to answer the question: if the # of presents is 70, then the answer would be YES but if the # of presents is greater than 180, then the answer would be NO. Not sufficient. (2) If each person in line had one more present to be wrapped, nine clerks would be required to guarantee that every present would be wrapped in one hour. Say 70 people in line have total of n presents. We are told that n+70 presents can be wrapped by 9 clerks. 9 clerks can for sure wrap 9*20=180 presents. Thus we are given that \(n+70\leq{180}\) > \(n\leq{110}\). So, there are at most 110 presents to be wrapped. To guarantee wrapping 110 presents minimum 6 clerks are needed (6 slowest clerks can wrap 120 presents). We don't know how many clerks are there at the counter. Not sufficient. (1)+(2) From (1) we know that there are 6 clerks, thus they can for sure wrap minimum 120 presents, since the # of presents is less than or equal 110, then these 6 can wrap all the presents. Sufficient. Answer: C. Hope it's clear.
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Hi,
=======================================
At a certain department store presentwrapping counter, each clerk will wrap no fewer than 20 and no more than 30 presents per hour. If seventy people are standing in line, will all of their presents be wrapped after one hour?
=======================================
So the slowest clerk can wrap 20 gifts
As a worst case the number of gifts wrapped in an hour is
20 * number of clerks.
=======================================
(1) Each person in line has at least one present to be wrapped by one of the six clerks at the counter.
=======================================
This does not give the number of gifts, hence is insufficient.
=======================================
(2)If each person in line had one more present to be wrapped, nine clerks would be required to guarantee that every present would be wrapped in one hour.
=======================================
This means that if there are 70 more gifts, nine clerks are needed.
If you can guarantee that 9 slow clerks can wrap all gifts in an hour, you can pretty much say any combination of clerks, slow or fast can do it within an hour.
Total number of gifts + 70 <= 9clerks * 20 Gifts wrapped by each
Total number of gifts <= 180  70
<= 110
However (2) does not give the number of clerks at the counter, hence is insufficient.
Using (1) and (2) together 
Number of clerks = 6
Number of gifts <= 110
Assume all 6 clerks are slow; They can wrap 120 gifts in an hour.
Since we have 110 or less, this can be done.
I'd say Answer is C.




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70 People
M clerk
N Present
1) Six Clerks No info about Presents Insufficient
2) Nine Clerks will guarantee N+70 presents
a. No Info about N so Insufficient
1+2 :
Analyze second in detailsâ€¦
9 Clerks =>
Min Number of packets (9*20 =180)
Max No of packets (9*30 =270)
So N can range from (18070, 27070) = (110, 200)
Add information about 6 Clerks at counter
6 clerks Min wrap packets (6*20 = 120)
6 clerks Max wrap packets (6*30 = 180)
Hence if there are more than 180 packets this condition is not satisfied
Answer E
Off course this is wrong otherwise I wouldnâ€™t be posting this question

OA is C:
9 people can wrap at least 9*20 = 180 presents
One more present per person so 18070 = 110 Present
1 Says we have 6 clerks 1+2 can answer question!
Any one agrees or this is Kaplanâ€™s Mistake!



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agree with C)
from stem we know that one clerk can wrap 30 gifts at most per hour. Seventy people on the line,
From A we know that there are six clerks and minimum 70 presents which is insufficient
From B) we can calculate the number of gifts in the people on the line 9x30=27070=200 approx. but we do not know how many clerks are currently working
combining both it is clear that 27070=200 presents hold the people in the line, currently there are 6 clerks working who can pack 30 gifts at most, so the clerks will not be able to complete the job in one hour



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I actually find this question confusing. Please correct me if I'm wrong.
Combining (1) and (2) we know that:
if (2) assumes that a clerk can wrap 20 gifts per hour, then we have 9*20=180, but since the customers have 1 more, subtract 70 >110
if (2) assumes that a clerk can wrap 30 gifts per hour, than we have 9*30=270, >200
If there are six clerks and they work at 20 g/h, in the case of 110 they would be able to wrap all the gifts, otherwise they wouldn't.
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thearch wrote: I actually find this question confusing. Please correct me if I'm wrong.
I also found this confusing... and my analysis was same as yours!
BG if you see my explaination of OA says C for different reason than your analysis!



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Yeah I think cool frequency has given an good explanation... it is C
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coolfrequency wrote: This means that if there are 70 more gifts, nine clerks are needed. If you can guarantee that 9 slow clerks can wrap all gifts in an hour, you can pretty much say any combination of clerks, slow or fast can do it within an hour.
Total number of gifts + 70 <= 9clerks * 20 Gifts wrapped by each Total number of gifts <= 180  70 <= 110
However (2) does not give the number of clerks at the counter, hence is insufficient.
Using (1) and (2) together  Number of clerks = 6 Number of gifts <= 110
Assume all 6 clerks are slow; They can wrap 120 gifts in an hour. Since we have 110 or less, this can be done.
I'd say Answer is C. I am lost on this one. Kaplan has a very similar solution noted too. However, instead of slowest case scenario, if I take the highest numbers: Total number of gifts + 70 <= 9clerks * 30 Gifts wrapped by each Total number of gifts <= 270  70 <= 200 Using (1) and (2) together  Number of clerks = 6 Number of gifts <= 200 Maximum gifts that can be wrapped 6 clerks: 6*30 = 180. Which contradicts the slow case and so the answer to the main question will be E. What am I missing?



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Re: At a certain department store presentwrapping counter, each
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20 Oct 2013, 10:27
Thanks Bunuel What I don't understand is, why did you choose the minimum speed as opposed to maximum in your calculation for n You used: n+70 <= 180 Why not: n+ 70 <=270
The statement says 9 clerks can wrap n+70 presents at a speed of between 20...30 presents per hour. Why choose 20 and not 30? Is it because of the use of the word "guarantee" in statement 2?



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Re: At a certain department store presentwrapping counter, each
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20 Oct 2013, 10:31



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Re: At a certain department store presentwrapping counter, each
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20 Oct 2013, 10:54
Ah! Damn important words hidden in plain sight.
Thanks Bunuel



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Re: At a certain department store presentwrapping counter, each
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20 Feb 2018, 17:59
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Re: At a certain department store presentwrapping counter, each &nbs
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