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B
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Difficulty:
55%
(hard)
Question Stats:
73% (03:11) correct
27%
(03:13)
wrong
based on 30
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At a certain fast food restaurant, Brian can buy 3 burgers, 7 shakes, and one order of fries for $ 120 exactly. At the same place it would cost $ 164.5 for 4 burgers, 10 shakes, and one order of fries. How much would it cost (in $) for an ordinary meal of one burger, one shake, and one order of fries?
A. 21
B. 31
C. 41
D. 51
E. 61
A. 21
B. 31
C. 41
D. 51
E. 61
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22 Jul 2022, 18:02
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pintukr
Let the cost of one burger be b dollars, the cost of one shake be s dollars, and the cost of one order of fries be f dollars. We are told that 3 burgers, 7 shakes, and one order of fries cost $120, so we can write:
\(\Rightarrow\) 3b + 7s + f = 120
We are also told that 4 burgers, 10 shakes, and one order of fries cost $164.5. Thus:
\(\Rightarrow\) 4b + 10s + f = 164.5
Let's multiply each side of the first equation by 3, and each side of the second equation by 2:
\(\Rightarrow\) 9b + 21s + 3f = 360
\(\Rightarrow\) 8b + 20s + 2f = 329
Let's subtract the second equation from the first:
\(\Rightarrow\) b + s + f = 31
We see that one burger, one shake, and one order of fries cost $31.
Answer: B
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
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