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At a certain fruit stand, the price of an apple is twice the price of

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At a certain fruit stand, the price of an apple is twice the price of  [#permalink]

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New post 21 May 2019, 00:21
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E

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At a certain fruit stand, the price of an apple is twice the price of an orange. For which of the following combinations of apples and oranges is the total price equal to the total price of 20 oranges?

I. 2 apples and 16 oranges
II. 3 apples and 14 oranges
III. 6 apples and 8 oranges

A. I only
B. II only
C. III only
D. I and II only
E. I, II and III

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Re: At a certain fruit stand, the price of an apple is twice the price of  [#permalink]

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New post 21 May 2019, 02:48
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Bunuel wrote:
At a certain fruit stand, the price of an apple is twice the price of an orange. For which of the following combinations of apples and oranges is the total price equal to the total price of 20 oranges?

I. 2 apples and 16 oranges
II. 3 apples and 14 oranges
III. 6 apples and 8 oranges

A. I only
B. II only
C. III only
D. I and II only
E. I, II and III


let orange = 2
and apple = 4
so 20 * 2; 40
we see that for all give options we get 40
IMO E
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Re: At a certain fruit stand, the price of an apple is twice the price of  [#permalink]

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New post 22 May 2019, 05:24
Bunuel wrote:
At a certain fruit stand, the price of an apple is twice the price of an orange. For which of the following combinations of apples and oranges is the total price equal to the total price of 20 oranges?

I. 2 apples and 16 oranges
II. 3 apples and 14 oranges
III. 6 apples and 8 oranges

A. I only
B. II only
C. III only
D. I and II only
E. I, II and III


Let the price of an orange = x

Then, price of an apple = 2x

Price of 20 oranges = 20x

Case 1 : 2 apples and 16 oranges

Price of 2 apples = 2*2x <------> Price of 16 oranges = 16x

2*2x + 16x = 20x

20x = 20x ----------- Valid

Case 2 : 3 apples and 14 oranges

Price of 3 apples = 3*2x <------> Price of 14 oranges = 14x

3*2x + 14x = 20x

20x = 20x ----------- Valid

Case 3 : 6 apples and 8 oranges

Price of 6 apples = 6*2x <------> Price of 8 oranges = 8x

6*2x + 8x = 20x

20x = 20x ----------- Valid

Hence E
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Re: At a certain fruit stand, the price of an apple is twice the price of  [#permalink]

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New post 22 May 2019, 05:37
Bunuel wrote:
At a certain fruit stand, the price of an apple is twice the price of an orange. For which of the following combinations of apples and oranges is the total price equal to the total price of 20 oranges?

I. 2 apples and 16 oranges
II. 3 apples and 14 oranges
III. 6 apples and 8 oranges

A. I only
B. II only
C. III only
D. I and II only
E. I, II and III


Cost of-
1 apple- 2x
1 orange- x
20 Oranges- 20x

I 4x+16X= 20X Yes
II 6x+14X==20X yes
III 12X + 8X=20X Yes.

Option E
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Re: At a certain fruit stand, the price of an apple is twice the price of  [#permalink]

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New post 27 May 2019, 05:36
Bunuel wrote:
At a certain fruit stand, the price of an apple is twice the price of an orange. For which of the following combinations of apples and oranges is the total price equal to the total price of 20 oranges?

I. 2 apples and 16 oranges
II. 3 apples and 14 oranges
III. 6 apples and 8 oranges

A. I only
B. II only
C. III only
D. I and II only
E. I, II and III


We can let the price of an apple be 2 dollars and the price of an orange be 1 dollar, so 20 oranges is 20 dollars.

Thus, we see that 2 apples and 16 oranges is 20 dollars, 3 apples and 14 oranges is 20 dollars, and 6 apples and 8 oranges is 20 dollars.

Answer: E
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Re: At a certain fruit stand, the price of an apple is twice the price of   [#permalink] 27 May 2019, 05:36
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