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08 Aug 2017, 23:58
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D
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Difficulty:
25%
(medium)
Question Stats:
75% (01:54) correct
25%
(02:03)
wrong
based on 117
sessions
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At a certain sales agency, each salesperson receives a monthly base salary of $2000, plus commission equal to 10% of her sales over $2500 for that month. How much did Allison earn in June?
(1) The amount that Allison earned in June was equal to 20% of her total sales for June.
(2) Had Allison sold $17500 more than she did in June, her total earnings would have equaled 15% of her sales.
(1) The amount that Allison earned in June was equal to 20% of her total sales for June.
(2) Had Allison sold $17500 more than she did in June, her total earnings would have equaled 15% of her sales.
09 Aug 2017, 00:17
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Bunuel
At a certain sales agency, each salesperson receives a monthly base salary of $2000, plus commission equal to 10% of her sales over $2500 for that month. How much did Allison earn in June?
(1) The amount that Allison earned in June was equal to 20% of her total sales for June.
(2) Had Allison sold $17500 more than she did in June, her total earnings would have equaled 15% of her sales.
(1) The amount that Allison earned in June was equal to 20% of her total sales for June.
(2) Had Allison sold $17500 more than she did in June, her total earnings would have equaled 15% of her sales.
Let sales in June be \(S\)
As per the question stem Income = 2000 + 10%*(S-2500) . Hence to calculate earning we need the value of \(S\)
Statement 1: Income = 20% of S
this implies 20% of S = 2000 + 10%*(S-2500) . this is a linear equation with only one unknown value \(S\), hence sufficient to find the value of S
Statement 2: Income = 15% of (S+ 17500)
this implies 15% of (S+ 17500) = 2000 + 10%*(S+17500-2500). a linear equation in \(S\). Hence the value of \(S\) can be found. Sufficient
Option \(D\)
09 Aug 2017, 01:22
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Option D
\(2000 + (X - 2500) * 0.1 = ?\)
Stmt 1
\(2000 + (X - 2500) * 0.1 = 0.2X\)
1 equation 1 variable --> can be solved
Stmt 2
\(2000 + (X + 15000)* 0.1 = 0.15(X + 17500)\)
again, 1 equation 1 variable --> can be solved
\(2000 + (X - 2500) * 0.1 = ?\)
Stmt 1
\(2000 + (X - 2500) * 0.1 = 0.2X\)
1 equation 1 variable --> can be solved
Stmt 2
\(2000 + (X + 15000)* 0.1 = 0.15(X + 17500)\)
again, 1 equation 1 variable --> can be solved
