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At a conference table, 5 employees gather around a table. One of the

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New post 26 May 2016, 12:27
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At a conference table, 5 employees gather around a table. One of the employees is the manager and he sits at the head of the table. Two of the employees sit on either side of the table. How many different seating arrangements can be made with these five employees?

(A) 5
(B) 10
(C) 24
(D) 32
(E) 120

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New post 26 May 2016, 14:31
Bunuel wrote:
At a conference table, 5 employees gather around a table. One of the employees is the manager and he sits at the head of the table. Two of the employees sit on either side of the table. How many different seating arrangements can be made with these five employees?

(A) 5
(B) 10
(C) 24
(D) 32
(E) 120



Head's sit is fixed. Now 4 people is left with 4 seats.

4 people can sit on 4 seats in 4! ways or 24 ways.

Ans is C
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New post 28 May 2016, 08:59
Head is fixed, 4 people left, there are 4! ways to sit them => 24 => C
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New post 28 Aug 2017, 12:10
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I did not get the meaning of 'Two of the employees sit on either side of the table.' If two of the employees sit on either side of the table then how is it 4!?
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New post 28 Aug 2017, 12:55
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devikeerthan wrote:
I did not get the meaning of If two of the employees sit on either side of the table then how is it 4!?


It seems to me they want us to get confused.

'Two of the employees sit on either side of the table.' It means nothing in this case.
So what? It is the same as 4 workers and 4 seats. So 4! ways.

Two of the employees have to sit on one particular side of the table. Different meaning - different answer.
Two of the employees have to sit one next to another. Different meaning - different answer.

What is good. There are no answer options that suit to these conditions. So it is impossible to make mistake.
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New post 03 Sep 2017, 06:09
1 question & 1 point:

1) For regular employees, if we have 4 different employees and 4 seats, shouldn't it be 4 seats * 4 employees=16 to get number of combinations? I've definitely seen that before. Like if you have 5 food options and 4 drink options you have 5*4=20 choices.

2) I guess we are supposed to assume that M can only sit in one spot instead of their being 2 ends of a table. Seems a bit ambiguous.

Thank you.
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New post 04 Jul 2018, 19:31
Bunuel wrote:
At a conference table, 5 employees gather around a table. One of the employees is the manager and he sits at the head of the table. Two of the employees sit on either side of the table. How many different seating arrangements can be made with these five employees?

(A) 5
(B) 10
(C) 24
(D) 32
(E) 120


Since the manager must sit at the head of the table, there are 4 chairs left. There are 4 choices for the first chair, 3 choices for the second, 2 choices for the third and 1 choice for the fourth. Therefore, the number of seating arrangement is:

4 x 3 x 2 x 1 = 4! = 24

Answer: C
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At a conference table, 5 employees gather around a table. One of the  [#permalink]

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New post 16 Jan 2019, 21:04
Bunuel wrote:
At a conference table, 5 employees gather around a table. One of the employees is the manager and he sits at the head of the table. Two of the employees sit on either side of the table. How many different seating arrangements can be made with these five employees?

(A) 5
(B) 10
(C) 24
(D) 32
(E) 120


Hello Bunuel,

Could you pls explain what is the meaning of "Two of the employees sit on either side of the table" ? in this question. I got confused because of this sentence.

Thanks,
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At a conference table, 5 employees gather around a table. One of the   [#permalink] 16 Jan 2019, 21:04
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