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At a football game between team A and team B, 95000 fans are in attend

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Joined: 07 Jun 2018
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At a football game between team A and team B, 95000 fans are in attend  [#permalink]

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New post 15 Dec 2018, 21:50
2
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

34% (02:33) correct 66% (02:51) wrong based on 41 sessions

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At a football game between team A and team B, 95000 fans are in attendance. Eighty percent of those fans are rooting for team A. An unknown number of team B fans leave the stadium, while all of the team A fans remain. Team A fans now comprise 95 percent of the total number of fans at the game. Assuming that none of the fans are fans of both team A and team B, how many team B fans are left in the stadium?

1. 4000

2. 4750

3. 10000

4. 15000

5. 19000
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Re: At a football game between team A and team B, 95000 fans are in attend  [#permalink]

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New post 15 Dec 2018, 23:15
Suppose total Attendance = 100
Team A supporter : 80
Team B Supporter: 20
Now some of team B supporter Leave Suppose: x
Total attendance after Some of B supporter leave: 100-x
Now given (100-x) * 0.95 = 80
95-0.95x =80
0.95x = 15
X= 15.8 ( for every 100 attendance)
For 95000
(15.8 * 95000) / 100
= approx. 15000

Answer D (4)

i think Given OA is wrong..
Please confirm Jazzmin
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Re: At a football game between team A and team B, 95000 fans are in attend  [#permalink]

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New post 16 Dec 2018, 00:12
Jazzmin wrote:
At a football game between team A and team B, 95000 fans are in attendance. Eighty percent of those fans are rooting for team A. An unknown number of team B fans leave the stadium, while all of the team A fans remain. Team A fans now comprise 95 percent of the total number of fans at the game. Assuming that none of the fans are fans of both team A and team B, how many team B fans are left in the stadium?

1. 4000

2. 4750

3. 10000

4. 15000

5. 19000



This is my approach
80 percent of the fans are rooting for team A which means 20 percent are rooting for team B since no players are rooting for both
80 percent of 95000 is 76000 root for team A and the rest 19000 root for team B
Now, x number of fans rooting for B leave the stadium.
So, 76000 comprise of 95 % of the stadium which means the rest 5% are left in the stadium which root for team B.
76000 is 95% of 80000.
Which means the rest 4000 are rooting for team B.
The question here is how many team B fans are left inside the stadium which is 4000
Your answer is correct if the question was ¨how many team B fans left the stadium¨
I hope this helps. Pls correct me if I am wrong.
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Re: At a football game between team A and team B, 95000 fans are in attend  [#permalink]

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New post 17 Dec 2018, 04:14
Since the number of fans of Team A is unchanged

We can Equate (80/100) * 95000 = (95/100) * x
Where x is the total number of fans left after some fans of Team B leave

By inspection x = 80000

Number of fans of Team B left in the stadium = 5% of 80000 = 4000
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Re: At a football game between team A and team B, 95000 fans are in attend  [#permalink]

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New post 25 Apr 2019, 06:19
1
let say,
The total of people, X = 95000


Before,
The number of A supporter, A = 0.8x ,
The number of B supporter, B = 0.2x

After,
The number of A supporter, A = 0.8x ,
The number of B supporter who leaves the game, m
The number of B supporter who remains in the game, C = 0.2x -m

Therefore,

A/(A + C) = 0.95
0.8X / (0.8x + C ) = 0.95
C = 4000
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Re: At a football game between team A and team B, 95000 fans are in attend   [#permalink] 25 Apr 2019, 06:19
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