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Arranging the scores in order:
14, 14, 14, a, 50, c, d, 65, 65
Since the median of all 9 applicants is 50, the 5th score is 50.

Analyzing Statement (1)
If the scores of 14 and 65 are removed, the remaining scores are:
a, 50, c, d
The median of these 4 numbers is 56, so:
(50+c)/2=56 so c=62
We still do not know a or d, so the average cannot be determined.
Statement (1) is insufficient.

Analyzing Statement (2)
The range of the remaining scores is 12.
This only tells us the difference between the highest and lowest remaining scores. Multiple sets of values are still possible, so the average cannot be determined.
Statement (2) is insufficient.

Combining Statements (1) and (2)
From statement (1), we know c=62.
Using the range of 12, different possibilities still exist, such as:
  • 50,50,62,62
  • 50,51,62,62
These give different averages.
So the average score still cannot be uniquely determined.
Correct Answer: E

Bunuel
At a music audition, judges assigned scores to 9 applicants. Among the applicants, 3 tied for the lowest score of 14 points, and 2 tied for the highest score of 65 points. If the median score of the 9 applicants was 50 points, what was the average (arithmetic mean) score of the 9 applicants?

(1) If the applicants who received 14 points or 65 points are not considered, the median score of the remaining applicants is 56 points.

(2) If the applicants who received 14 points or 65 points are not considered, the range of the remaining scores is 12 points.

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Good attempt from both posters, but just to be precise: the answer is E, and here's exactly why the combination still fails.

First, let's set up the sorted sequence correctly. We have 9 scores with 3 tied at 14 (lowest) and 2 tied at 65 (highest). The 5th score is the median = 50. So the full ordered list looks like:

14, 14, 14, a, 50, c, d, 65, 65

where a <= 50 and 50 <= c <= d <= 65.

1. Statement (1) alone: Remove the 14s and 65s. The remaining 4 scores are a, 50, c, d. Their median is (50+c)/2 = 56, which gives c = 62. Now I know one of the four middle values, but a and d are still floating. Not sufficient.

2. Statement (2) alone: Range of those same 4 remaining scores = 12, meaning d - a = 12. No idea what c is, no individual values pinned down. Not sufficient.

3. Together: From S1 I get c = 62. From S2 I get d - a = 12. My sum is:

Total = 14(3) + a + 50 + 62 + d + 65(2) = 42 + a + 50 + 62 + d + 130 = 284 + a + d

Since d - a = 12, I can write d = a + 12, so a + d = 2a + 12. But a can still vary. Try a = 50, d = 62 or a = 49, d = 61 — these give different sums. Still not sufficient.

The trap here is classic Data Sufficiency: people assume that because two statements together feel like "complete information," you must get a unique answer. But range only constrains the difference, not the actual values. The sum never locks in.

Answer: E
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d cannot be 61, because we already know c is 62, so d won't be less than c as per your logic too..
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Good attempt from both posters, but just to be precise: the answer is E, and here's exactly why the combination still fails.

First, let's set up the sorted sequence correctly. We have 9 scores with 3 tied at 14 (lowest) and 2 tied at 65 (highest). The 5th score is the median = 50. So the full ordered list looks like:

14, 14, 14, a, 50, c, d, 65, 65

where a <= 50 and 50 <= c <= d <= 65.

1. Statement (1) alone: Remove the 14s and 65s. The remaining 4 scores are a, 50, c, d. Their median is (50+c)/2 = 56, which gives c = 62. Now I know one of the four middle values, but a and d are still floating. Not sufficient.

2. Statement (2) alone: Range of those same 4 remaining scores = 12, meaning d - a = 12. No idea what c is, no individual values pinned down. Not sufficient.

3. Together: From S1 I get c = 62. From S2 I get d - a = 12. My sum is:

Total = 14(3) + a + 50 + 62 + d + 65(2) = 42 + a + 50 + 62 + d + 130 = 284 + a + d

Since d - a = 12, I can write d = a + 12, so a + d = 2a + 12. But a can still vary. Try a = 50, d = 62 or a = 49, d = 61 — these give different sums. Still not sufficient.

The trap here is classic Data Sufficiency: people assume that because two statements together feel like "complete information," you must get a unique answer. But range only constrains the difference, not the actual values. The sum never locks in.

Answer: E
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I do not think a can be 49. Since after combining, we get b and c as 50 and 62 respectively, also given that range is 12, a and d must be between 50 and 62 inclusive. If a is 49, range becomes 62(c)- 49(a) = 13.
Edskore
Good attempt from both posters, but just to be precise: the answer is E, and here's exactly why the combination still fails.

First, let's set up the sorted sequence correctly. We have 9 scores with 3 tied at 14 (lowest) and 2 tied at 65 (highest). The 5th score is the median = 50. So the full ordered list looks like:

14, 14, 14, a, 50, c, d, 65, 65

where a <= 50 and 50 <= c <= d <= 65.

1. Statement (1) alone: Remove the 14s and 65s. The remaining 4 scores are a, 50, c, d. Their median is (50+c)/2 = 56, which gives c = 62. Now I know one of the four middle values, but a and d are still floating. Not sufficient.

2. Statement (2) alone: Range of those same 4 remaining scores = 12, meaning d - a = 12. No idea what c is, no individual values pinned down. Not sufficient.

3. Together: From S1 I get c = 62. From S2 I get d - a = 12. My sum is:

Total = 14(3) + a + 50 + 62 + d + 65(2) = 42 + a + 50 + 62 + d + 130 = 284 + a + d

Since d - a = 12, I can write d = a + 12, so a + d = 2a + 12. But a can still vary. Try a = 50, d = 62 or a = 49, d = 61 — these give different sums. Still not sufficient.

The trap here is classic Data Sufficiency: people assume that because two statements together feel like "complete information," you must get a unique answer. But range only constrains the difference, not the actual values. The sum never locks in.

Answer: E
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1. the first choice is enough to find the 6th value as ; 50+6th=56*2 or 6th value=62
still we don't know 4th and 7th values so not sufficient to find the mean.
2. the second choice just tells that (7th value = 4th value+12) still not sufficient
on combining 1 and 2 , 7th value can have values as 62 or 63 or 64. (less than 65 and more than or equal to 62).
however (63 or 64) - 12=51 or 52 respectively are 4th value, hence can be discarded as are more than the 5th value.
so only value that satisfies 7th value=62 so 4th value=50
now all values known 14,14,14,50,50,62,62,65,65 sufficient to find the mean.
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