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02 May 2025, 03:33
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
61% (01:41) correct
39%
(01:42)
wrong
based on 106
sessions
History
Date
Time
Result
Not Attempted Yet
At an animal shelter, each cat and each dog received exactly one treat: either Treat A or Treat B. 84 of the cats received Treat A, and 48 of the dogs received Treat B. How many of the animals received Treat A?
(1) 60% of the cats received Treat A.
(2) 60% of the dogs received Treat B.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
(1) 60% of the cats received Treat A.
(2) 60% of the dogs received Treat B.
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
11 May 2025, 06:30
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Bookmarks
Official Solution:
At an animal shelter, each cat and each dog received exactly one treat: either Treat A or Treat B. 84 of the cats received Treat A, and 48 of the dogs received Treat B. How many of the animals received Treat A?
(1) 60% of the cats received Treat A.
This gives \(0.6C = 84\), so \(C = 140\). Hence, 84 cats received Treat A, and the remaining 140 - 84 = 56 cats received Treat B. From this we can deduce that 56 (cats) + 48 (dogs) = 104 of the animals received Treat B. However, the number of dogs receiving Treat A is not known. Not sufficient.
(2) 60% of the dogs received Treat B.
This gives \(0.6D = 48\), so \(D = 80\). Hence, 48 dogs received Treat B, and the remaining 80 - 48 = 32 dogs received Treat A. Therefore, a total of 84 (cats) + 32 (dogs) = 116 of the animals received Treat A. Sufficient.
Answer: B
At an animal shelter, each cat and each dog received exactly one treat: either Treat A or Treat B. 84 of the cats received Treat A, and 48 of the dogs received Treat B. How many of the animals received Treat A?
(1) 60% of the cats received Treat A.
This gives \(0.6C = 84\), so \(C = 140\). Hence, 84 cats received Treat A, and the remaining 140 - 84 = 56 cats received Treat B. From this we can deduce that 56 (cats) + 48 (dogs) = 104 of the animals received Treat B. However, the number of dogs receiving Treat A is not known. Not sufficient.
(2) 60% of the dogs received Treat B.
This gives \(0.6D = 48\), so \(D = 80\). Hence, 48 dogs received Treat B, and the remaining 80 - 48 = 32 dogs received Treat A. Therefore, a total of 84 (cats) + 32 (dogs) = 116 of the animals received Treat A. Sufficient.
Answer: B
General Discussion
02 May 2025, 03:54
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Bunuel
Given that all animals ( cat or dog)in the shelter, either receives Treat A or Treat B.
| Treat A | Treat B | Total | |
| CAT | 84 | x | |
| DOG | Y | 48 | |
| Total |
We need to find how many animals received Treat A? 84+Y =?
Statement 1:
(1) 60% of the cats received Treat A.
60% of cats = 84
100% of cat = (84*100)/60 = 140.
cats = Treat A + Treat B = 84 + x = 140. Thus x = 56
This statement is not Suffcient to find Y. Hence, Insufficient
Statement 2:
(2) 60% of the dogs received Treat B.
60% of dog = 48
Y = 40% of dog = ?
Y = (40*48) / 60
Y = 32
we need to find : 84+Y = 84+32 = 116.
Option B is Sufficient.
