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28 Jan 2025, 17:13
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Managers: 100
Designers: 140
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
72% (02:43) correct
28%
(03:02)
wrong
based on 1396
sessions
History
Date
Time
Result
Not Attempted Yet
At Company Z's engineering division, an employee is classified either as a manager or an engineer. The division is made up of 80% engineers and 35% of those engineers are designers. None of the designers are managers.
Which of the following could be the number of managers and designers in the engineering division?
Which of the following could be the number of managers and designers in the engineering division?
| Managers | Designers | |
| 35 | ||
| 70 | ||
| 80 | ||
| 100 | ||
| 140 | ||
| 280 |
ShowHide Answer
Official Answer
Managers: 100
Designers: 140
28 Jan 2025, 21:31
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So, you know that 20% of employees are managers, but how many are designers? 35% of 80% is (80/20)*7 = 28
Now that you know that 20% of employees are managers and 28% are designers, you need to see which number n could fit such that 20n and 28n are integers that fit the above options.
The first number for which 28 ends in a 0 is 5 which is 140 that'll mean there's 5*20 = 100 managers and 140 designers.
Now that you know that 20% of employees are managers and 28% are designers, you need to see which number n could fit such that 20n and 28n are integers that fit the above options.
The first number for which 28 ends in a 0 is 5 which is 140 that'll mean there's 5*20 = 100 managers and 140 designers.
29 Jan 2025, 13:00
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1. The question asks us to find a possible combination of the number of managers and designers.
2. Let the number of employees in the engineering division be N.
3. 80% of them are engineers and the rest are managers. That means the number of managers is 0.2N.
4. 35% of the 80% are designers, or \(0.35 * 0.8\)N = 0.28N.
5. We're given no other information, so in order to deduce a possible combination, we should look at the ratio between designers and managers, or \(\frac{0.28}{0.2} = \frac{28}{20} = \frac{14}{10} = \frac{7}{5}\).
6. The only combination that has this ratio is 140 and 100.
7. Our answer will be: Managers - 100 and Designers - 140.
2. Let the number of employees in the engineering division be N.
3. 80% of them are engineers and the rest are managers. That means the number of managers is 0.2N.
4. 35% of the 80% are designers, or \(0.35 * 0.8\)N = 0.28N.
5. We're given no other information, so in order to deduce a possible combination, we should look at the ratio between designers and managers, or \(\frac{0.28}{0.2} = \frac{28}{20} = \frac{14}{10} = \frac{7}{5}\).
6. The only combination that has this ratio is 140 and 100.
7. Our answer will be: Managers - 100 and Designers - 140.
