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B
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Difficulty:
95%
(hard)
Question Stats:
33% (02:54) correct
67%
(02:12)
wrong
based on 24
sessions
History
Date
Time
Result
Not Attempted Yet
At Giovanni’s, a meal consists of two or three courses—first (3 options), second (4 options), and third (3 options)—and one beverage. What is the minimum number of beverage options required to allow at least 365 distinct meals?
A. 5
B. 6
C. 7
D. 10
E. 11
A. 5
B. 6
C. 7
D. 10
E. 11
31 Mar 2026, 06:59
Kudos
Bookmarks
3 course meal selections = 3C1 * 4C1 * 3C1 = 3 * 4* 3 =36 Options
2 course meals can be made using - First & second, First & third, Second & third options = (3C1 * 4C1) + (3C1 * 3C1) + (4C1 * 3C1) = (3*4) + (3*3) +(4*3) = 12 + 9 + 12 = 33 Options
If we add beverage options then,
3 course meal options = 36 * nC1
2 course meal options = 33 * nC1
(36 * nC1) + (33 * nC1) >= 365
69 * nC1 >= 365
nC1 >= 365/69
n >= 365/69
n >= 5.2
Answer should be : B
2 course meals can be made using - First & second, First & third, Second & third options = (3C1 * 4C1) + (3C1 * 3C1) + (4C1 * 3C1) = (3*4) + (3*3) +(4*3) = 12 + 9 + 12 = 33 Options
If we add beverage options then,
3 course meal options = 36 * nC1
2 course meal options = 33 * nC1
(36 * nC1) + (33 * nC1) >= 365
69 * nC1 >= 365
nC1 >= 365/69
n >= 365/69
n >= 5.2
Answer should be : B
31 Mar 2026, 06:59
Kudos
Bookmarks
3 course meal selections = 3C1 * 4C1 * 3C1 = 3 * 4* 3 =36 Options
2 course meals can be made using - First & second, First & third, Second & third options = (3C1 * 4C1) + (3C1 * 3C1) + (4C1 * 3C1) = (3*4) + (3*3) +(4*3) = 12 + 9 + 12 = 33 Options
If we add beverage options then,
3 course meal options = 36 * nC1
2 course meal options = 33 * nC1
(36 * nC1) + (33 * nC1) >= 365
69 * nC1 >= 365
nC1 >= 365/69
n >= 365/69
n >= 5.2
Answer should be : B
2 course meals can be made using - First & second, First & third, Second & third options = (3C1 * 4C1) + (3C1 * 3C1) + (4C1 * 3C1) = (3*4) + (3*3) +(4*3) = 12 + 9 + 12 = 33 Options
If we add beverage options then,
3 course meal options = 36 * nC1
2 course meal options = 33 * nC1
(36 * nC1) + (33 * nC1) >= 365
69 * nC1 >= 365
nC1 >= 365/69
n >= 365/69
n >= 5.2
Answer should be : B
