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At least 100 students at a certain high school study japanes [#permalink]
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At least 100 students at a certain high school study Japanese. If 4 percent of the studetns at the school who study French also study Japanese, do more students at the school study french than Japanese? (1) 16 students at the school study both French and Japanese (2) 10 percent of the students at the school who study Japanese also study French.
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Last edited by Bunuel on 31 Jan 2013, 02:59, edited 2 times in total.
Edited the question and added the OA



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Re: Japanese studetns [#permalink]
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number of japanese students >= 100 number of students who study japanese and french = 4% of french students
st 1) 16 studens study both japanese and french = 4% of french studens so number of french students = 16 * 100/4 = 400 but we dont know how many studetns study japanese. Not sufficient
st 2) number of students who study japanese and french = 10% of japanese = 4% of french so french studens > japanese students Sufficient
B



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harikattamudi wrote: Atleast 100 students at a certain high school study Japanes. If 4 Percent of the students at the school who study French also study Japanes, do more students at the school study French than Japanes
1.16 Students at the school study both French and japanese. 2.10 Percent of the students at the school who study Japanese also study French
Please explain the way to solve these kind of probelms.
Thanks H Is it B? 1. 16 students study both F and J, so there are 400 students studying F: insuff 2. 10% J study F while 4%F study J, so the number of students studying F is greater than that of studens studying J



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We have J >= 100, and 0.04F also study Japanese.
1. 16 students study both French and Japanese. This means 400 students study French, since 4% of 400 is 16, however we don't know how many students study Japanese. INSUFF
2. This tells us 0.1J also study French. This number is actually identical to 0.04F because it represents the same quantity, which is the number of students who study both French and Japanese!
=> 0.1J = 0.04F => J = 0.4F Thus more students study Japanese than French! Sufficient
Pick B



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Re: word problem [#permalink]
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27 Jun 2010, 02:18
IMO, it cannot be B:
The 4% is for J&F not F alone (Thus it comprises students who study both Japanese and French). Hence, the statement 10% of J = 4 % of F is not correct. If we combine the two statements, we will get a definite answer:
From (1), we get F=400 From (2), we get 10% of J = 4% of J&F. From (1), J&F=16, therefore, if 10% of J = 16, J=160. Thus J<F. The two statements combined are sufficient.
Correct me if I am wrong...
Thus, my ans. is (C).



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Re: word problem [#permalink]
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27 Jun 2010, 05:15
dagmat wrote: IMO, it cannot be B:
The 4% is for J&F not F alone (Thus it comprises students who study both Japanese and French). Hence, the statement 10% of J = 4 % of F is not correct. If we combine the two statements, we will get a definite answer:
From (1), we get F=400 From (2), we get 10% of J = 4% of J&F. From (1), J&F=16, therefore, if 10% of J = 16, J=160. Thus J<F. The two statements combined are sufficient.
Correct me if I am wrong...
Thus, my ans. is (C). OA for this question is B. Let # of students who study Japanese be \(J\), the # of of students who study French be \(F\) and # of students who study Japanese and French be \(F&J\). From stem # of students who study Japanese and French is 4% of the # of students who study French > \(F&J=4%F\); From (2) # of students who study Japanese and French is 10% of the # of students who study Japanese (so MORE share of the same group) > \(F&J=10%J\). So, \(10%J=4%F\) > \(\frac{F}{J}=2.5\) > \(F>J\).
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Re: word problem [#permalink]
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28 Jun 2010, 04:38
At least 100 students at a certain high school study japanese. If 4 percent of the studetns at the school who study french also study japanese, do more students at the school study french than japanese? 1) 16 students at the school study both french and japanese 2) 10 percent of the students at the schoool who study japanese also study french. Let's put it this way... From (1) > 16 students study both F&J = 4% of F So F = 400, but we don't know how many students who study J coz they said "AT LEAST 100"
From (2) > 10%J = 4%F > we know that F is greater than J because only 4% of F is equal to 10% of J
So B is correct



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Re: overlap sets [#permalink]
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15 Aug 2010, 20:56
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Hi, Statement 1: 16 students study F and J. There should be 400 students studying F. The number of J students could be any of 300 or 400 or 500 (lesser or greater? cannot tell). Statement 2: Let x be the number of students who study F and J. x is 4% of F x is 10% of J. This implies that J is definitely lesser than F. Hence, sufficient. Hope this helps. Thanks.
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lalithajob wrote: At least 100 students at a certain high school study Japanese. If 4 percent of the students at the school who study French also study Japanese, do more students at the school study French than Japanese?
1) 16 students at the school study both French and Japanese. 2) 10 percent of the students at the school who study Japanese also study French. Let J represent the set of students studying Japanese and F represent the set of students studying French F^J is the set of students studying both Japanese and French From the question J>=100 , .04F= F^J , is F>J ? 1) F^J=16 => .04F =16 => F=400 . We still don't have any information about J. It can >=100. If 100<= j<400 , F>J. Otherwise F<=J. So not sufficient 2) .1J = F^J => .1J=.04F => F = 2.5 J . Clearly F is bigger than J. So sufficient Answer B
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Re: French & Japanese [#permalink]
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19 Feb 2012, 19:15
Answer should be E. Here is how: Question: At least \(100\) students at a certain high school study Japanese. If \(4\) percent of the students at the school who study French also study Japanese, do more students at the school study French than Japanese?Statement A: \(16\) students at the school study both French and Japanese. We know that \(4%\) of the students who study french also study Japanese, which means that of those who study french, \(4%\) also study Japanese and there are \(16\) such people. So we can set up an equation as below: Let \(x=\) no of people who study french. So: \(\frac{4}{100}*(x)=16\) so \(x=400\) , so \(400\) people study French but we the number of Japanese students is greater than \(100\) and we do not know the exact number so japanese students could be less than \(400\) or greater than \(400\). Hence Insufficient. Statement B: 10 percent of the students at the school who study Japanese also study French. From Statement B we can see that: \(4%\) of French Students \(= 10%\) of Japanese Students So definitely the number of French Students is greater. Hence Sufficient. Answer B.
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Re: At least 100 students at a certain high school study japanes [#permalink]
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13 Nov 2013, 01:05
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"At least 100 studies Japanese". Is it trap? No one explains anything about it.
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Re: At least 100 students at a certain high school study japanes [#permalink]
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At least 100 students at a certain high school study japanes [#permalink]
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24 May 2015, 17:27
amitgovin wrote: At least 100 students at a certain high school study Japanese. If 4 percent of the studetns at the school who study French also study Japanese, do more students at the school study french than Japanese?
(1) 16 students at the school study both French and Japanese (2) 10 percent of the students at the school who study Japanese also study French. Simply put: Students who study both languages represent 4% of all French students (given in the Q) but 10% of all Japanese students (Statement 2). The number of French students then has to be higher than Japanese students. Only 2 is sufficient.



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Re: At least 100 students at a certain high school study japanes [#permalink]
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26 May 2015, 23:44
This question can also be solved by using venn diagram. Interpreting the Given InfoThe question tells us about students in a school studying Japanese and French. Let's represent them using a venn diagram. a  Number of students who study only Japanese b  Students who study both Japanese and French c Students who study only French d Students who study neither Japanese nor French We are given that atleast 100 students study Japanese i.e. a + b => 100Also we are told that 4% of the students who study French also study Japanese i.e. 4%(b + c) = b. It can be simplified to c = 24bWe are asked to find if there are more students at the school who study French than Japanese i.e. if b + c > b + a, which simplifies to c > a?We can either i. find the values of c and a to answer the question or ii. express a in terms of b and then compare it with c to answer the question. Let's see if the statements provide us with the required information. StatementIStI tells us that 16 students study both French and Japanese i.e. b = 16. This would give us a => 84 and c = 384. As a => 84, a > 384 or a < 384. Since we do not have a definite value of a we can't say for sure if c > a. Hence stI is insufficient to answer the question. StatementIIStII tells us that 10% of the students who study French also study Japanese i.e. 10%(a + b) = b i.e. a = 9b. Now, we have a and c both in terms of b. We see that c =24b and a = 9b i.e. c > a . Hence stII is sufficient to answer the question. Hope this helps Regards Harsh
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Re: At least 100 students at a certain high school study japanes [#permalink]
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12 Oct 2015, 04:26
Bunuel wrote: amitgovin wrote: At least 100 students at a certain high school study japanese. If 4 percent of the studetns at the school who study french also study japanese, do more students at the school study french than japanese?
1) 16 students at the school study both french and japanese
2) 10 percent of the students at the schoool who study japanese also study french.
please explain. thanks. Given: \(J\geq{100}\) and \(0.04*F=Both\) Q: is \(F>J\)? (1) \(Both=16=0.04*F\) > \(F=400\). We don't know \(J\). Not sufficient (2) \(0.1*J=Both=0.04*F\) (given) > \(0.1*J=0.04*F\) > \(\frac{F}{J}=\frac{10}{4}\) > \(F>J\). Sufficient. Answer: B Hi Bunuel, How should one interpret "If 4 percent of the students at the school who study French also study Japanese" I took it in this way Suppose total num of students who know F =100 So 4% of this know both J and F , this doesn't mean that the entire number of students who know both F & J is 4 Its just telling out of 100 french 4 know both J and F and further if it is stated that out of 200 J students 20 know both Then total no of students who know J & F is 24. After viewing your explanation ,came to know that "If 4 percent of the students at the school who study French also study Japanese" talks about the entire num of students who know J & F not just subset. Can you let us know how to avoid such blunders.



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Re: At least 100 students at a certain high school study japanes [#permalink]
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27 Nov 2015, 06:04
Information from question stem: 1) j > 100 2) .04f also study Japanese. Question: f > j?
Statement 1: .04f = 16, therefore f = 400, however j >100, therefore j < or > f. INSUFF.
Statement 2: .1j = .04f, j = 2/5f, therefore j < f. SUFF
Answer is B.



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Re: At least 100 students at a certain high school study japanes [#permalink]
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27 Nov 2015, 06:19
Bunuel, I tried to solve this question by grid method. But questions like these take a lot of time by grid method. But few questions are very easy to be solved using grid method. Can you suggest at what point of time in the problem should we abort using the grid method while solving a particular problem and start again from the scratch? Bunuel wrote: amitgovin wrote: At least 100 students at a certain high school study japanese. If 4 percent of the studetns at the school who study french also study japanese, do more students at the school study french than japanese?
1) 16 students at the school study both french and japanese
2) 10 percent of the students at the schoool who study japanese also study french.
please explain. thanks. Given: \(J\geq{100}\) and \(0.04*F=Both\) Q: is \(F>J\)? (1) \(Both=16=0.04*F\) > \(F=400\). We don't know \(J\). Not sufficient (2) \(0.1*J=Both=0.04*F\) (given) > \(0.1*J=0.04*F\) > \(\frac{F}{J}=\frac{10}{4}\) > \(F>J\). Sufficient. Answer: B
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At least 100 students at a certain high school study japanes [#permalink]
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12 Sep 2017, 04:50
Bunuel wrote: amitgovin wrote: At least 100 students at a certain high school study japanese. If 4 percent of the studetns at the school who study french also study japanese, do more students at the school study french than japanese?
1) 16 students at the school study both french and japanese
2) 10 percent of the students at the schoool who study japanese also study french.
please explain. thanks. Given: \(J\geq{100}\) and \(0.04*F=Both\) Q: is \(F>J\)? (1) \(Both=16=0.04*F\) > \(F=400\). We don't know \(J\). Not sufficient (2) \(0.1*J=Both=0.04*F\) (given) > \(0.1*J=0.04*F\) > \(\frac{F}{J}=\frac{10}{4}\) > \(F>J\). Sufficient. Answer: B  Hi Bunuel, So, "4 percent of the students at the school who study french also study japanese" and "10 percent of the students at the school who study japanese also study french"  these 2 are the same group of people?



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Re: At least 100 students at a certain high school study japanes [#permalink]
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12 Sep 2017, 04:58
SinhaS wrote: Bunuel wrote: amitgovin wrote: At least 100 students at a certain high school study japanese. If 4 percent of the studetns at the school who study french also study japanese, do more students at the school study french than japanese?
1) 16 students at the school study both french and japanese
2) 10 percent of the students at the schoool who study japanese also study french.
please explain. thanks. Given: \(J\geq{100}\) and \(0.04*F=Both\) Q: is \(F>J\)? (1) \(Both=16=0.04*F\) > \(F=400\). We don't know \(J\). Not sufficient (2) \(0.1*J=Both=0.04*F\) (given) > \(0.1*J=0.04*F\) > \(\frac{F}{J}=\frac{10}{4}\) > \(F>J\). Sufficient. Answer: B  Hi Bunuel, So, "4 percent of the students at the school who study french also study japanese" and "10 percent of the students at the school who study japanese also study french"  these 2 are the same group of people? Yes. Students who study french and also study japanese are those who study both languages the same way students who study japanese and also study french are also those are those who study both languages.
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