bmwhype2
At noon, Paul stopped at a gas station and filled his car's 50 litre tank to its capacity. After he drove 75 miles away from the station, the tank developed a leak and the car started to lose 1/5 litres of fuel per minute. If he is travelling at a constant speed of 50 miles per hour and his car consumes 10 litres every 100 miles, what time will his car stop moving?
4 pm
4:15 pm
4:30 pm
5:00 pm
5:20 pm
12pm, 50 liter
After 75 miles, gas consumption only, 10/100 * 75 = 7.5 liter, so 42.5 liter left, time taken 1/50*75 = 1.5 hour, so in sum:
1.30pm, 42.5 liter
Beyond 75 mile, you have leak and gas consumption
leak = 1/5 liter/min
consume = 10/100 liter/mile
Set x = distance in miles
Set t = total time in hour
10/100 * x = total consume
x = 50t
So we have:
(1) 5t = total consume
(2) 1/5 * 60t = 12t = total leak
Looking for t:
42.5 - 12t - 5t = 0
42.5 = 17t
t = 2.5 hour
Therefore, the car will stop at 2.5 hour after 1.30pm
Ans = 4pm