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23 Apr 2005, 18:49
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Baseball team consists of 20 players, 5 of whom are pitchers and 15 position players. If the batting order consists of 8 differnet position players and 1 pticher, and if the pitcher is always last in the order, then how many different batting orders are there for this baseball team?
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23 Apr 2005, 22:35
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We are picking ordered combinations of 8 from 15.
It is 8P15 = 15!/(15-8)!
For each ordered combination we are independetly picking one out of 5 pitchers.
X = 5 * 15! / 7!
It is 8P15 = 15!/(15-8)!
For each ordered combination we are independetly picking one out of 5 pitchers.
X = 5 * 15! / 7!
: (15*14*13*12*11*10*9*8)*5
