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Beerus and Champa are two of the twenty players on a softball team

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Beerus and Champa are two of the twenty players on a softball team  [#permalink]

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New post 05 Oct 2018, 07:12
1
1
6
00:00
A
B
C
D
E

Difficulty:

  85% (hard)

Question Stats:

39% (01:51) correct 61% (01:30) wrong based on 60 sessions

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Beerus and Champa are two of the twenty players on a softball team. If twelve runs were scored in a particular game, how many runs did Champa score?
1) The ratio of the number of runs Beerus scored to those that Champa scored was 1 to 3.
2) Had 3 more runs been scored, Champa's runs would have represented \(\frac{2}{5}\) of the total runs scored in the game.

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Re: Beerus and Champa are two of the twenty players on a softball team  [#permalink]

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New post 09 Oct 2018, 06:42
The answer is E, although i got it wrong because of being careless.
Explanation:
1 just tells us the ratio of two players out of 20. Thus clearly insufficient.
2 tells us that if there were 3 more runs scored i.e if the score was 15, then champa would have scored 2/3 rd of the score.
In this scenario there are different possible cases.

One would be that those 3 runs are scored by someone instead of champa. Then champa's score is 2/3 x 15 = 6.
The second case would be that the extra 3 runs are scored by champa himself. This would mean that Champas new score is 2/3 x 15 = 6. And his original score was 6 - 3 = 3.

Thus there are two possible answers, insufficient.

Even after combining both 1 and 2 we are left with the same 2 possible scores. Thus insufficient.
Answer is E
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Re: Beerus and Champa are two of the twenty players on a softball team   [#permalink] 09 Oct 2018, 06:42
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Beerus and Champa are two of the twenty players on a softball team

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