|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
15 Feb 2023, 00:13
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
69% (02:33) correct
31%
(02:21)
wrong
based on 313
sessions
History
Date
Time
Result
Not Attempted Yet
Bo profits $6.06 every time he sells a kebab and $0.79 every time he sells a pita. Yesterday, Bo only sold kebabs and pitas, and he sold total of 214 kebabs and pitas. Was Bo's profit more than $700 yesterday?
(1) Bo sold more pitas than kebabs yesterday
(2) Bo sold fewer than 64 kebabs yesterday
(1) Bo sold more pitas than kebabs yesterday
(2) Bo sold fewer than 64 kebabs yesterday
17 Feb 2023, 23:30
Kudos
Bookmarks
Bunuel
(1) Bo sold more pitas than kebabs yesterday
If \(108\) pitas and \(106\) Kebabs then profit :
From Pitas \(108*.79 =85.32\)
From Kebabs \(106*6.06= 642.36 \)
Total Profit \(= 642.36 +85.32 =727.68 \) Yes to the stem.
If \(213\) Pitas and \(1\) Kebab then profit:
From Pitas \(213 * .79 = 168.27\)
From Kebabs \(1* 6.06 = 6.06 \)
Total Profit \(168.27 +6.06 = 174.33 \) No to the stem.
INSUFF.
(2) Bo sold fewer than \(64 \) kebabs yesterday
So lets say he sold maximum # of Kebabs i.e \(63\) then profit from Kebabs \(63*6.06= 381.78\)
And profit from Pitas \(= 151 * .79 =119.29\)
Total \(= 381.78 +119.29 = 501.07\\
\)
So Bo's total profit cannot exceed \(700 \) if # of kebabs is less than \(64 \)
SUFF.
Ans B
Hope it helps .
General Discussion
18 Oct 2025, 12:37
Kudos
Bookmarks
As per the question it's given that:
Profit per kebab = $6.06
Profit per pita = $0.79
Total items sold = 214 (kebabs + pitas)
We need to know whether Bo’s total profit > $700.
Let:
k = number of kebabs sold
p = number of pitas sold
Then:
k+p = 214
Bo’s profit:
6.06k+0.79p
We need to know whether:
6.06k+0.79p>700
Expressing profit in terms of k only.
Since p=214−k
Profit=6.06k+0.79(214−k)
=6.06k+169.06−0.79k
=5.27k+169.06
We need to check if:
5.27k+169.06>700
Simplify:
5.27k>530.94
k>530.94/5.27 = 100.74(approx)
So Bo’s profit > $700 if and only if Bo sold more than 100.74 kebabs, i.e., at least 101 kebabs.
Now check the statements:
(1) Bo sold more pitas than kebabs.
That means p>k
From k+p=214, this implies:
p>107 ⟹ k<107
(Since if p>107, then k<107)
But k could be anywhere less than 107, for example:
Statement (1) is insufficient.
(2) Bo sold fewer than 64 kebabs.
That means k<64
Let’s test with k=63 (maximum possible under this condition):
Profit=5.27(63)+169.06=332.01+169.06=501.07
→ Profit = $501.07 < $700
For any smaller k, profit will be even lower.
So profit is definitely less than $700.
Statement (2) alone is sufficient.
Final answer:- Statement (2) alone is sufficient, but (1) alone is not. ->Correct answer is (B)
Profit per kebab = $6.06
Profit per pita = $0.79
Total items sold = 214 (kebabs + pitas)
We need to know whether Bo’s total profit > $700.
Let:
k = number of kebabs sold
p = number of pitas sold
Then:
k+p = 214
Bo’s profit:
6.06k+0.79p
We need to know whether:
6.06k+0.79p>700
Expressing profit in terms of k only.
Since p=214−k
Profit=6.06k+0.79(214−k)
=6.06k+169.06−0.79k
=5.27k+169.06
We need to check if:
5.27k+169.06>700
Simplify:
5.27k>530.94
k>530.94/5.27 = 100.74(approx)
So Bo’s profit > $700 if and only if Bo sold more than 100.74 kebabs, i.e., at least 101 kebabs.
Now check the statements:
(1) Bo sold more pitas than kebabs.
That means p>k
From k+p=214, this implies:
p>107 ⟹ k<107
(Since if p>107, then k<107)
But k could be anywhere less than 107, for example:
- If k=50, profit = 5.27(50)+169.06=432.56 → < 700
- If k=106, profit = 5.27(106)+169.06=727.68 → > 700
Statement (1) is insufficient.
(2) Bo sold fewer than 64 kebabs.
That means k<64
Let’s test with k=63 (maximum possible under this condition):
Profit=5.27(63)+169.06=332.01+169.06=501.07
→ Profit = $501.07 < $700
For any smaller k, profit will be even lower.
So profit is definitely less than $700.
Statement (2) alone is sufficient.
Final answer:- Statement (2) alone is sufficient, but (1) alone is not. ->Correct answer is (B)
