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26 Jan 2026, 06:33
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
67% (03:10) correct
33%
(03:34)
wrong
based on 78
sessions
History
Date
Time
Result
Not Attempted Yet
BOLTBUS left town P for town Q. Due to the traffic jam on the way, it stopped for half an hour and by this time it had covered a distance of 300 miles, which is 60% of the total distance. After the blockade cleared, the bus resumed the journey and the driver increased the speed by 20 miles per hour and reached town Q on the scheduled time. What was the initial speed of the bus?
A. 120 miles per hour
B. 110 miles per hour
C. 90 miles per hour
D. 85 miles per hour
E. 80 miles per hour
A. 120 miles per hour
B. 110 miles per hour
C. 90 miles per hour
D. 85 miles per hour
E. 80 miles per hour
26 Jan 2026, 08:33
Kudos
Bookmarks
The bus covered 300 miles, which is 60% of the total distance, so the total distance is 500 miles. The remaining distance is 200 miles. It stopped for 0.5 hours after the first 300 miles.
Scheduled Time
Let the original speed be r mph. The scheduled time for the entire trip is 500/r hours.
Actual Journey Time
Time for first 300 miles: \(\frac{300}{r}\) hours.
After stop, speed is r+20 mph, so time for remaining 200 miles: \(\frac{200}{r+20}\) hours.
Total actual time: \(\frac{300}{r}\) + 0.5 + \(\frac{200}{r+20} \)hours, which equals the scheduled time.
ANS = E
Scheduled Time
Let the original speed be r mph. The scheduled time for the entire trip is 500/r hours.
Actual Journey Time
Time for first 300 miles: \(\frac{300}{r}\) hours.
After stop, speed is r+20 mph, so time for remaining 200 miles: \(\frac{200}{r+20}\) hours.
Total actual time: \(\frac{300}{r}\) + 0.5 + \(\frac{200}{r+20} \)hours, which equals the scheduled time.
ANS = E
