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Both Robert and Yvonne can translate news summaries from French into English and from English into French, but at different rates in documents per hour, as shown below:
.............French to English........English to French
Robert...........5..............................1..........................
Yvonne..........2..............................6..........................
This week, they have to translate in total 50 news summaries from French to English and 150 news summaries from English to French. They cannot work on any new summaries together,and, except when there is only one document left to be translated, neither can work while is the other is not working. What is the difference between the maximum and minimum number of hours that Yvonne could spend working on translating news summaries this week?
(A) 20 hours (B) 22 hours and 30 minutes (C) 22 hours and 40 minutes (D) 24 hours and 10 minutes (E) 24 hours and 30 minutes
.............French to English........English to French
Robert...........5..............................1..........................
Yvonne..........2..............................6..........................
This week, they have to translate in total 50 news summaries from French to English and 150 news summaries from English to French. They cannot work on any new summaries together,and, except when there is only one document left to be translated, neither can work while is the other is not working. What is the difference between the maximum and minimum number of hours that Yvonne could spend working on translating news summaries this week?
(A) 20 hours (B) 22 hours and 30 minutes (C) 22 hours and 40 minutes (D) 24 hours and 10 minutes (E) 24 hours and 30 minutes
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07 Aug 2006, 12:51
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kevincan
max hours: when Y works on F-E and R works on E-F:
when Y finishes the whole F-E in 25 hours, R sinishes 25 E-F.
for remaining (150 -25 = 125) E-F, they, each, take 125/7 = 17 hours but there still remain 6 E-F summaries in which Y finishes 5 in 50 minuets.
so the max time taken by Y = 25 + 17.5 = 42.5 hours
min hours: when R works on F-E and Y works on E-F:
when R finishes the whole F-E in 10 hours, Y finishes 60 E-F.
for remaining (150 - 60 = 90) E-F, they, each, take 90/7 = 12 hours. again there remain 6 E-F summaries in which Y finishes 5 in 50 minuets.
so the min time taken by Y = 10 + 12.5 = 22.5 hours
diff = 42.5 - 22.5 = 20 hours
didi i miss something???????
07 Aug 2006, 13:11
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No, you didn't! I make a mistake writing the choices!
OA and OE above
OA and OE above
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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
