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Bowl X has 4 cards in it, numbered 1-4. Bowl Y has 5 cards in it, numb

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Bowl X has 4 cards in it, numbered 1-4. Bowl Y has 5 cards in it, numb [#permalink]

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New post 28 Jan 2018, 23:38
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Bowl X has 4 cards in it, numbered 1-4. Bowl Y has 5 cards in it, numbered 5-9. What is the probability that the product of a card pulled randomly from Bowl X and a card pulled randomly from Bowl Y will be even?

A. 3/20
B. 3/10
C. 5/8
D. 7/10
E. 1/2

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Re: Bowl X has 4 cards in it, numbered 1-4. Bowl Y has 5 cards in it, numb [#permalink]

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New post 28 Jan 2018, 23:53
D

We know that even numbers are formed in three cases. O*E, E*O, E*E.

Case 1 (O*E):

Probability of Odd from X=2/4
Probability of Even from Y=2/5

Probability = 2/4*2/5 = 4/20

Case 2 (E*O):

Probability of Even from X=2/4
Probability of Odd from Y=3/5

Probability = 2/4*3/5 = 6/20

Case 3 (E*E):

Probability of Even from X=2/4
Probability of Even from Y=2/5

Probability = 2/4*2/5 = 4/20

Hence total probability = 4/20+6/20+4/20 = 14/20 = 7/10
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Re: Bowl X has 4 cards in it, numbered 1-4. Bowl Y has 5 cards in it, numb   [#permalink] 28 Jan 2018, 23:53
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