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24 Apr 2006, 12:51
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Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length. The length of each red stick is 18 inches less than the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average (arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?
A. 3
B. 6
C. 12
D. 18
E. 24
A. 3
B. 6
C. 12
D. 18
E. 24
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24 Apr 2006, 14:31
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E 24
let R be lenght of any red stick
W be average length of blue and red stick in box w
V be average length of blue and red stick in box v
according to question R = W -18 ----- eqn 1
also R = V +6 ------ eqn 2
equating the both equation we get W-18 =V +6
===> W -V = 24
hence 24 .
let R be lenght of any red stick
W be average length of blue and red stick in box w
V be average length of blue and red stick in box v
according to question R = W -18 ----- eqn 1
also R = V +6 ------ eqn 2
equating the both equation we get W-18 =V +6
===> W -V = 24
hence 24 .
