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rhyme
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rhyme
dosa_don
Avi-great stuff. Now you can buy me some beer :lol: when did you submit btw?

Correlation(submission_date, interview_invite_date) = 0.0000000



Correlation(strength of app, interview_invite_date) = ?
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rhyme
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Avi-great stuff. Now you can buy me some beer :lol: when did you submit btw?

Correlation(submission_date, interview_invite_date) = 0.0000000


Then:
Correlation(interview_invite_date,admission_result_is_positive)=X

Please solve for X

The longest day in my life, and I still have the FOMC to go...
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kwam
rhyme
dosa_don
Avi-great stuff. Now you can buy me some beer :lol: when did you submit btw?

Correlation(submission_date, interview_invite_date) = 0.0000000

Then:
Correlation(interview_invite_date,admission_result_is_positive)=X

Please solve for X

The longest day in my life, and I still have the FOMC to go...


Correlation(strength of app, interview_invite_date) = 0.95
Correlation(interview_invite_date,admission_result_is_positive)= 0.0

The hypergeometric distribution describes the probability that in a sample of n distinctive objects drawn from the application exactly k objects are denied. In general, if a random variable X follows the hypergeometric distribution with parameters N, m and n, then the probability of getting exactly k successes is given by

f(k;N,m,n) = {{{m \choose k} {{N-m} \choose {n-k}}}\over {N \choose n}}.

The probability is positive when k is between max(0, n+m−N) and min{m, n).

The formula can be understood as follows: There are \tbinom{N}{n} possible samples (without replacement). There are \tbinom{m}{k} ways to obtain k defective objects and there are \tbinom{N-m}{n-k} ways to fill out the rest of the sample with non-defective objects.

The fact that the sum of the probabilities, as k runs through the range of possible values, is equal to 1, is essentially Vandermonde's identity from combinatorics.

Duh.
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rhyme


The hypergeometric distribution describes the probability that in a sample of n distinctive objects drawn from the application exactly k objects are denied. In general, if a random variable X follows the hypergeometric distribution with parameters N, m and n, then the probability of getting exactly k successes is given by

f(k;N,m,n) = {{{m \choose k} {{N-m} \choose {n-k}}}\over {N \choose n}}.

The probability is positive when k is between max(0, n+m−N) and min{m, n).

The formula can be understood as follows: There are \tbinom{N}{n} possible samples (without replacement). There are \tbinom{m}{k} ways to obtain k defective objects and there are \tbinom{N-m}{n-k} ways to fill out the rest of the sample with non-defective objects.

The fact that the sum of the probabilities, as k runs through the range of possible values, is equal to 1, is essentially Vandermonde's identity from combinatorics.

Duh.


Errrr... confess, did you just make it up?
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wow... that was hot! :shock:
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given m+n > N and m,n,N are positive real numbers
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aviroop
YIPPPEEEEEEE

I got the interview invite.....
email just came in

I danced in my cubicle

but now I am worried.

Perhaps my app is that bad coz they want to evaluate me and kick me out fasttt


Congrats!
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This is fantastic news, avi !! Congratulations !! And all the best for the interview !! :)
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Thanks collegesenior and mneo..I wish some more gsbers get invites..I am checking this thread every 10 minutes.
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aviroop
Thanks collegesenior and mneo..I wish some more gsbers get invites..I am checking this thread every 10 minutes.


5pm, one day down, many many more to go. I have to say this is a lot more fun to watch from this side of the fence than it was from the other side of the fence. I'm still rootin for ya here.
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helg
rhyme


The hypergeometric distribution describes the probability that in a sample of n distinctive objects drawn from the application exactly k objects are denied. In general, if a random variable X follows the hypergeometric distribution with parameters N, m and n, then the probability of getting exactly k successes is given by

f(k;N,m,n) = {{{m \choose k} {{N-m} \choose {n-k}}}\over {N \choose n}}.

The probability is positive when k is between max(0, n+m−N) and min{m, n).

The formula can be understood as follows: There are \tbinom{N}{n} possible samples (without replacement). There are \tbinom{m}{k} ways to obtain k defective objects and there are \tbinom{N-m}{n-k} ways to fill out the rest of the sample with non-defective objects.

The fact that the sum of the probabilities, as k runs through the range of possible values, is equal to 1, is essentially Vandermonde's identity from combinatorics.

Duh.

Errrr... confess, did you just make it up?


no i cut and paste from wikipedia lol
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Rhyme looking at last years thread is keeping me sane at this point. You didn't get an invite for what a week or so? That just shows that timing isn't everything. 14 days to go.
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riverripper
Rhyme looking at last years thread is keeping me sane at this point. You didn't get an invite for what a week or so? That just shows that timing isn't everything. 14 days to go.

yea, looking at the invites and acceptances you see there is no correlation to when you get the invite.
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i checked my admission's status every hour in case the email went to spam.

NOTHING.
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At the BW forum 3 got interviews...

What a tough day, I did not have idea how was hard to play this game, perhaps it's easier to play the game which you have no clue when they may call you... Perhaps I'm just too anxious :lol:
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CfaMiami
i checked my admission's status every hour in case the email went to spam.

NOTHING.


Its still day 1... stay strong.
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Well done Avi ... well deserved.
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