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# Can anyone define the operator for the square? I tried

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Manager
Joined: 29 Apr 2003
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Can anyone define the operator for the square? I tried [#permalink]

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18 Aug 2003, 13:06
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Can anyone define the operator for the square?
I tried addition, subtraction, division, and multiplication, and I could not get the result.
Manager
Joined: 10 Jun 2003
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18 Aug 2003, 14:06
You have misinterpreted the problem. This type of problem "invents" a new operator, defined in the question stem. Follow the patten that it shows you to get the answer.
Manager
Joined: 14 Aug 2003
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18 Aug 2003, 15:28
Manager
Joined: 29 Apr 2003
Posts: 93
Location: Singapore
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Kudos [?]: 0 [0], given: 0

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19 Aug 2003, 07:03
Well done to all of you.

Just in case for those who still could not catch it, and I have just figured it.

Column A

Try to substitute x=0, and y=2 into the equation.

Column B

Try to substitute x = -1, and y = -1 into the equation.
19 Aug 2003, 07:03
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