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Circle C is drawn with center at (0,0) and radius = 4. If a

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Joined: 04 Dec 2005
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Circle C is drawn with center at (0,0) and radius = 4. If a [#permalink]

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New post 17 Jan 2007, 13:46
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Circle C is drawn with center at (0,0) and radius = 4. If a line L passes through (rt(2), -rt(2)) is drawn perpendicular to C, what is the slope of line L?

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New post 17 Jan 2007, 14:31
L perpendicular to C implies that L is the support of a radius of the circle.

As the circle is centered at 0(0,0), the equation of the line L is of the kind :
y = a*x.

Also, the line passes by (sqrt(2),-sqrt(2)) gives us
-sqrt(2) = sqrt(2)*a
<=> a = -1

Hence, the slope is thus equal to -1.

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New post 11 Nov 2008, 09:59
Hi
I did nt really understand the meaning of support radius
Can anyone explain

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New post 11 Nov 2008, 12:03
hibloom wrote:
Hi
I did nt really understand the meaning of support radius
Can anyone explain



A line passing through a given point and perpendicular to the circle will pass through the center of the circle.

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Re: Question 4   [#permalink] 11 Nov 2008, 12:03
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Circle C is drawn with center at (0,0) and radius = 4. If a

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