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Area will be slightly greater than pi/5 + 4.Considering the sum of all the 3 segments.
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Bunuel,

The explanation is clear till here-
1. Draw a square.
2. Diagonal of the square = sqrt( 4*2 + 4*2) = 4
3. Diagonal of the square = diameter of circle = 4
4. Radius of the circle = 2
5. Area of circle = 4*pi
6. Area of square = 2 sqrt(2) * 2 sqrt(2) = 2*4 = 8

Can you please solve/explain it further?
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honchos
Bunuel,

The explanation is clear till here-
1. Draw a square.
2. Diagonal of the square = sqrt( 4*2 + 4*2) = 4
3. Diagonal of the square = diameter of circle = 4
4. Radius of the circle = 2
5. Area of circle = 4*pi
6. Area of square = 2 sqrt(2) * 2 sqrt(2) = 2*4 = 8

Can you please solve/explain it further?


Radius of circle = 2

Area of circle between chords is 4 + 4\sqrt{2}

Area of circle - area of circle between chords = 4pi - (4+4\sqrt{2})
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honchos
Bunuel,

The explanation is clear till here-
1. Draw a square.
2. Diagonal of the square = sqrt( 4*2 + 4*2) = 4
3. Diagonal of the square = diameter of circle = 4
4. Radius of the circle = 2
5. Area of circle = 4*pi
6. Area of square = 2 sqrt(2) * 2 sqrt(2) = 2*4 = 8

Can you please solve/explain it further?

The idea here is to consider symmetry of the figure. You see the figure inscribed inside a circle is a square, so the left out portions will be divided symmetrically i,e \(\frac{4pi-8}{4}\).

so 2 of these 4 portions belong to the square in the figure(central segment) which is why the central portion is 8+2(pi-2) and other two portions are segment 1 and 2.

the question could have been made tougher if you had a rectangle ,, then you would have to need consider the areas of arcs.

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