fskilnik wrote:
[GMATH practice question]
Circle (x-3)^2 + (y-1)^2 = 13 intersects the vertical axis in two points which are p units apart. What is the value of p?
(A) 1/2
(B) 1
(C) 2
(D) 3
(E) 4
\(? = p\)
\(\left\{ \begin{gathered}
{\left( {x - 3} \right)^2} + {\left( {y - 1} \right)^2} = 13 \hfill \\
x = 0 \hfill \\
\end{gathered} \right.\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\left( {y - 1} \right)^2} = 4\,\,\,\,\, \Rightarrow \,\,\,\left\{ \begin{gathered}
y - 1 = - 2 \hfill \\
\,\,\,\,\,{\text{OR}} \hfill \\
y - 1 = 2 \hfill \\
\end{gathered} \right.\)
\(\left\{ \begin{gathered}
x = 0\,\,\,;\,\,\,y - 1 = - 2\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{\text{point}}\,\,\,A = \,\,\left( {0, - 1} \right) \hfill \\
\,\,\,\,\,{\text{OR}} \hfill \\
x = 0\,\,\,;\,\,\,y - 1 = 2\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{\text{point}}\,\,B = \left( {0,3} \right) \hfill \\
\end{gathered} \right.\,\,\,\,\,\,\)
\(? = p = {\text{dist}}\left( {A,B} \right) = 4\)
This solution follows the notations and rationale taught in the GMATH method.
Regards,
Fabio.
_________________
Fabio Skilnik ::
GMATH method creator (Math for the GMAT)
Our high-level "quant" preparation starts here:
https://gmath.net