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# combination rules

Author Message
Intern
Joined: 28 Apr 2018
Posts: 13

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Updated on: 20 Sep 2018, 12:01
What is the solution of nC4 < 3Cn ?

A n>7
B n<7
C n>4
D n<3
E n>1

Originally posted by Godsent on 09 Sep 2018, 09:57.
Last edited by Godsent on 20 Sep 2018, 12:01, edited 3 times in total.
Senior Manager
Joined: 18 Jun 2018
Posts: 260

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14 Sep 2018, 07:44
please update OA and source of the question.
Intern
Joined: 28 Apr 2018
Posts: 13

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17 Sep 2018, 13:01
nc4<3cn

n!/4![n-4]!<n!/3![n-3]!

n(n-1)(n-2)(n-3)/4!<n(n-1)(n-2)/3!

(n-3)/24<1/6

n-3<4

n<7
Senior Manager
Joined: 18 Jun 2018
Posts: 260

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17 Sep 2018, 20:01
Godsent wrote:
nc4<3cn

n!/4![n-4]!<n!/3![n-3]!

n(n-1)(n-2)(n-3)/4!<n(n-1)(n-2)/3!

(n-3)/24<1/6

n-3<4

n<7

In Question, it is specified 3Cn
Re: combination rules &nbs [#permalink] 17 Sep 2018, 20:01
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# combination rules

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