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# COMBINATIONS

Author Message
Manager
Joined: 04 Sep 2006
Posts: 113

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02 Feb 2009, 11:36
q; IN HOW MANY WAYS CAN 8 DIFFERENT BOOKS BE EVENLY DISTRIBUTED BY FOUR PERSONS?

630 840 1260 1830 2520

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SVP
Joined: 07 Nov 2007
Posts: 1738
Location: New York

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02 Feb 2009, 12:03
1
vcbabu wrote:
q; IN HOW MANY WAYS CAN 8 DIFFERENT BOOKS BE EVENLY DISTRIBUTED BY FOUR PERSONS?

630 840 1260 1830 2520

Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260
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SVP
Joined: 29 Aug 2007
Posts: 2427

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02 Feb 2009, 12:36
x2suresh wrote:
vcbabu wrote:
q; IN HOW MANY WAYS CAN 8 DIFFERENT BOOKS BE EVENLY DISTRIBUTED BY FOUR PERSONS?

630 840 1260 1830 2520

Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260

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SVP
Joined: 07 Nov 2007
Posts: 1738
Location: New York

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03 Feb 2009, 16:59
vcbabu wrote:

Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260

You have 8 books and 4 people

= (fist person select 2 out of 8 books) *(second person select 2 out of 6 books) *(third person select 2 out of 4 books) *(fourth person select 2 out of 2 books) *
= 8C2*6C2*4C2*2C2 = 1260
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Intern
Joined: 31 Jan 2009
Posts: 10
Schools: UTA, Fuqua, UNC, Yale, Colombia

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04 Feb 2009, 17:40
Sorry but what is C2 in this problem? Not sure how you came up to 1260.
Director
Joined: 29 Aug 2005
Posts: 818

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05 Feb 2009, 01:36
x2suresh wrote:
vcbabu wrote:

Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260

You have 8 books and 4 people

= (fist person select 2 out of 8 books) *(second person select 2 out of 6 books) *(third person select 2 out of 4 books) *(fourth person select 2 out of 2 books) *
= 8C2*6C2*4C2*2C2 = 1260

Does this not result in 2520?
Manager
Joined: 13 Jan 2009
Posts: 162

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05 Feb 2009, 05:26
Agree with 1260. What is the OA?
Manager
Joined: 13 Jan 2009
Posts: 162

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05 Feb 2009, 05:27
Agree with 1260. What is the OA?
Manager
Joined: 01 May 2008
Posts: 107
Location: São Paulo

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07 Feb 2009, 11:18
botirvoy wrote:
x2suresh wrote:
vcbabu wrote:

Its same as 4 people selecting 2 books each.

= 8C2*6C2*4C2*2C2 = 1260

You have 8 books and 4 people

= (fist person select 2 out of 8 books) *(second person select 2 out of 6 books) *(third person select 2 out of 4 books) *(fourth person select 2 out of 2 books) *
= 8C2*6C2*4C2*2C2 = 1260

Does this not result in 2520?

I agee. The result of that is 2520, not 1260.
SVP
Joined: 07 Nov 2007
Posts: 1738
Location: New York

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07 Feb 2009, 13:06
Yeap!! it should be 2520

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

_________________

Smiling wins more friends than frowning

Re: COMBINATIONS   [#permalink] 07 Feb 2009, 13:06
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# COMBINATIONS

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