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Company X has 6 regional offices. Each regional office must recommend

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Company X has 6 regional offices. Each regional office must recommend [#permalink]

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Company X has 6 regional offices. Each regional office must recommend two candidates, one male and one female, to serve on the corporate auditing committee. If each of the offices must be represented by exactly one member on the auditing committee and if the committee must consist of an equal number of male and female employees, how many different committees can be formed?
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Last edited by Bunuel on 05 Jun 2016, 11:57, edited 1 time in total.
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Re: Company X has 6 regional offices. Each regional office must recommend [#permalink]

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This is an easy question. I tried again and I was able to solve. :lol:

As the question says, If each of the offices must be represented by exactly one member on the auditing committee and there are 6 Regional Offices, so each of the regional offices will be represented by 6 members on the auditing committee.

Also, as per question, committee must consist of an equal number of male and female employees that is 3 Male members and 3 Female members. So, the question is now simply reduced to the possible number of arrangements for MMMBBB.

It can be done in 6!/3!3! ways that is equal to 20.
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Trying my best..... will succeed definitely! :)

The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long.
+1 Kudos if you find this post helpful. :)

Do Check OG 2017 SC Solutions - http://gmatwithcj.com/solutions-gmat-official-guide-2017-sentence-correction-questions/

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Re: Company X has 6 regional offices. Each regional office must recommend [#permalink]

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New post 05 Jun 2016, 21:31
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vnigam21 wrote:
This is an easy question. I tried again and I was able to solve. :lol:

As the question says, If each of the offices must be represented by exactly one member on the auditing committee and there are 6 Regional Offices, so each of the regional offices will be represented by 6 members on the auditing committee.

Also, as per question, committee must consist of an equal number of male and female employees that is 3 Male members and 3 Female members. So, the question is now simply reduced to the possible number of arrangements for MMMBBB.

It can be done in 6!/3!3! ways that is equal to 20.


This question is of selection and not of arrangement. Please review.

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Re: Company X has 6 regional offices. Each regional office must recommend [#permalink]

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New post 05 Jun 2016, 22:06
chetan2u Abhishek009, please tell me what m i missing here
Each office has two candidates M and F , so this way we got 6 M and 6 F
now question says only 1 M or F will be represent his/her office.
so my understanding says if M is selected than his counterpart F will not, and vice versa.
So 6M and 6F
so selection will be 6c3*3c3
where 6c3 represents 3 males out of 6 and 3c3 represents remaining 3 females , which are not male counterpart.
similarly we have case for female 6c3 * 3c3
so ultimatly we 2 6c3= 40.
Please correct me where I am wrong.

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Re: Company X has 6 regional offices. Each regional office must recommend [#permalink]

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New post 06 Jun 2016, 02:18
sudhirmadaan wrote:
chetan2u Abhishek009, please tell me what m i missing here
Each office has two candidates M and F , so this way we got 6 M and 6 F
now question says only 1 M or F will be represent his/her office.
so my understanding says if M is selected than his counterpart F will not, and vice versa.
So 6M and 6F
so selection will be 6c3*3c3
where 6c3 represents 3 males out of 6 and 3c3 represents remaining 3 females , which are not male counterpart.
similarly we have case for female 6c3 * 3c3
so ultimatly we 2 6c3= 40.
Please correct me where I am wrong.


Hi,

the method or formula you are working on, is not correct here...

when you make a group of 3 from 6, the other group is automatically made as only 3 are left after choosing initial 3, and the same will be applicable here ..

Ways to divide 2 groups of 3 each from 6 members....
say ABCDEF are 6 persons and you choose ABC in 6C3, another group DEF is automaticaly formed..
so when you choose DEF in 6C3, ABC is also formed and thus there is a repetition and that is why divison by 2!..
ans 6C3/2!.....
But as you have found 2 * 6C3, which ACTUALLY should be\(2*\frac{6C3}{2!} = 6C3.\)....

SOLUTION : Another way :-

Let the 6 companies be ABCDEF..
Now the 3 we choose in 6C3 send male and the remaining 3 will send female....
so we basically find HOW many ways 2 teams of 3 each can be choosen out of 6 = 6!/3!3!2!= 10..

But each team will once send MALE and other time FEMALE ...
so ans = 10*2 = 20
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Re: Company X has 6 regional offices. Each regional office must recommend [#permalink]

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Re: Company X has 6 regional offices. Each regional office must recommend   [#permalink] 24 Nov 2017, 11:35
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