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07 Aug 2008, 22:31
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B
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Difficulty:
45%
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Question Stats:
72% (02:14) correct
28%
(02:21)
wrong
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Computer A requires 36 hours to process data. If Computer A starts working at 7 pm on Monday, and Computer B, which is three times as fast as Computer A, joins in after half the data is processed, when will the data processing be complete?
A. 4:30 pm on Tuesday
B. 5:30 pm on Tuesday
C. 7:00 pm on Tuesday
D. 8:30 pm on Tuesday
E. 10:30 pm on Tuesday
M18-12
A. 4:30 pm on Tuesday
B. 5:30 pm on Tuesday
C. 7:00 pm on Tuesday
D. 8:30 pm on Tuesday
E. 10:30 pm on Tuesday
M18-12
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12 Nov 2014, 02:25
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Rate of Computer A = \(\frac{1}{36}\)
Rate of Computer B = \(\frac{1}{12}\)
\(\frac{1}{2}\) Job completed by Computer A alone; means time consumed by Computer A \(= \frac{1}{2} * 36 = 18\) Hrs
Combined rate of A & B \(= (\frac{1}{36} + \frac{1}{12}) = \frac{1}{9}\)
Time required to complete remaining \(\frac{1}{2}\) Job \(= \frac{1}{2} * \frac{9}{1} = 4.5 Hrs\)
Total Time required to complete job = 18 + 4.5 = 22.5 Hrs
24 Hrs is SAME TIME next day, so 22.5 Hrs would be
7PM Tuesday - 1.5 Hrs = 5:30 PM Tuesday
Answer = B
Rate of Computer B = \(\frac{1}{12}\)
\(\frac{1}{2}\) Job completed by Computer A alone; means time consumed by Computer A \(= \frac{1}{2} * 36 = 18\) Hrs
Combined rate of A & B \(= (\frac{1}{36} + \frac{1}{12}) = \frac{1}{9}\)
Time required to complete remaining \(\frac{1}{2}\) Job \(= \frac{1}{2} * \frac{9}{1} = 4.5 Hrs\)
Total Time required to complete job = 18 + 4.5 = 22.5 Hrs
24 Hrs is SAME TIME next day, so 22.5 Hrs would be
7PM Tuesday - 1.5 Hrs = 5:30 PM Tuesday
Answer = B
08 Aug 2008, 08:42
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mba9now
computer A take 36 hr
computer B takes 12 hr
18 hrs (half job done by computer) + Half job dont by both
= 18 hrs + 18 / (3+1) = 22.5 hrs.
B is the answer
