Last visit was: 10 Jun 2026, 09:02 It is currently 10 Jun 2026, 09:02
Home
Messages
MBA Fair
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
qurenmoon
User avatar
Joined: 06 Jan 2010
Last visit: 09 Mar 2013
Posts: 16
Own Kudos:
2
Posts: 16
Kudos: 2
Confused Questions 23 Jan 2010, 06:12
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi All, I get confused on the following 2 questions.

1. If the average return journey time over 10 days is 30 minutes, but on the first outward journey a hold up added 30 minutes to that journey, by how much did the delay increase the daily average?
( my answer is 1.5 minutes)

2. If it takes one person 5 hours to load a truck while another person can complete the task in 3 hours, how ling it takes them to half fill the truck if they work together at the same rate?
(my answer is x/5+x/3=1/2, x=15/16 hour)

Unfortunately, none of my answers is correct! what's the problem?



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
silasaaa2
User avatar
Joined: 26 Nov 2009
Last visit: 29 Apr 2012
Posts: 53
Own Kudos:
75
Given Kudos: 5
GPA: 3.32
Posts: 53
Kudos: 75
Confused Questions 23 Jan 2010, 10:47
Kudos
Add Kudos
Bookmarks
Bookmark this Post
please post the answer choices
User avatar
mrblack
User avatar
Joined: 27 Apr 2008
Last visit: 06 May 2013
Posts: 135
Own Kudos:
236
Given Kudos: 1
Posts: 135
Kudos: 236
Confused Questions 24 Jan 2010, 18:47
Kudos
Add Kudos
Bookmarks
Bookmark this Post
For question 1), is the answer 3 mins?

Let X represent the average time to travel for each day (excluding the 30 mins extra on the first day). Thus we have the equation:

Average time = \(\frac{(X+30)+9X}{10}=30\)

X=27

Therefore, the holdup increased the average time by 3 mins.
User avatar
mrblack
User avatar
Joined: 27 Apr 2008
Last visit: 06 May 2013
Posts: 135
Own Kudos:
236
Given Kudos: 1
Posts: 135
Kudos: 236
Confused Questions 24 Jan 2010, 18:55
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Your answer to question 2) should be right. Plug in to check:
\((\frac{1 truck}{5 hours})(\frac{15}{16}hours)+(\frac{1 truck}{3 hours})(\frac{15}{16}hours) = \frac{8}{16}truck\)
User avatar
qurenmoon
User avatar
Joined: 06 Jan 2010
Last visit: 09 Mar 2013
Posts: 16
Own Kudos:
2
Posts: 16
Kudos: 2
Confused Questions 27 Jan 2010, 07:08
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mrblack
For question 1), is the answer 3 mins?

Let X represent the average time to travel for each day (excluding the 30 mins extra on the first day). Thus we have the equation:

Average time = \(\frac{(X+30)+9X}{10}=30\)

X=27

Therefore, the holdup increased the average time by 3 mins.
Show more

What's the meaning of "first outward journey"? In my opinion, this is a go-back journey. so it needs totally 20 days.
my equation is:Delay 30/(10+10)=1.5 m
User avatar
qurenmoon
User avatar
Joined: 06 Jan 2010
Last visit: 09 Mar 2013
Posts: 16
Own Kudos:
2
Posts: 16
Kudos: 2
Confused Questions 27 Jan 2010, 07:12
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mrblack
Your answer to question 2) should be right. Plug in to check:
\((\frac{1 truck}{5 hours})(\frac{15}{16}hours)+(\frac{1 truck}{3 hours})(\frac{15}{16}hours) = \frac{8}{16}truck\)
Show more

I really agree with you!
User avatar
DestinyChild
User avatar
Joined: 02 Oct 2009
Last visit: 23 Apr 2010
Posts: 124
Own Kudos:
82
Given Kudos: 4
Posts: 124
Kudos: 82
Confused Questions 27 Jan 2010, 10:50
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mrblack is on the money...!

clarity lies in the assumption that 30 mins is average time; like saying your car does 30mpg on an average...BUT... so going back on the question again... for the first phase 30mins of hold is added... and that is rest 9 days average holds steady... but for the first day it adds 30 mins of additional time...



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!