Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1310:00 AM EST
-12:00 PM EST
Have you ever wondered how to score a PERFECT 805 on the GMAT? Meet Julia, a banking professional who used the Target Test Prep course to achieve this incredible feat. Julia's story is nothing short of an inspiration.
Dec 1410:00 AM EST
-12:00 PM EST
Think a 100% GMAT Verbal score is out of your reach? Target Test Prep will make you think again! Our course uses techniques such as topical study and spaced repetition to maximize knowledge retention and make studying simple and fun.
Dec 1411:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.- Dec 15
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
93% (01:48) correct
7%
(02:41)
wrong
based on 14
sessions
History
Date
Time
Result
Not Attempted Yet
Consider a sequence of seven consecutive integers. The average of the first five integers is \(n\). The average of all the seven integers is:
A. \(n\)
B. \(n+1\)
C. \(k*n\), where \(k\) is a function of \(n\)
D. \(n+\frac{2}{7}\)
E. \(n+2\)
A. \(n\)
B. \(n+1\)
C. \(k*n\), where \(k\) is a function of \(n\)
D. \(n+\frac{2}{7}\)
E. \(n+2\)
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
09 Sep 2017, 01:52
Kudos
Bookmarks
niks18
Consider a sequence of seven consecutive integers. The average of the first five integers is \(n\). The average of all the seven integers is:
A. \(n\)
B. \(n+1\)
C. \(k*n\), where \(k\) is a function of \(n\)
D. \(n+\frac{2}{7}\)
E. \(n+2\)
A. \(n\)
B. \(n+1\)
C. \(k*n\), where \(k\) is a function of \(n\)
D. \(n+\frac{2}{7}\)
E. \(n+2\)
In case of a set of consecutive numbers, Middle number = Average of set
Set of 5 numbers - a, a+1, a+2, a+3, a+4
Middle number = Average = a+2
but we are given that average for first 5 numbers is = n
hence a+2 = n
Set of 7 numbers - a, a+1, a+2, a+3, a+4, a+5, a+6
Middle number = Average = a+3 = (a+2) + 1 = n+1
**********************************************************************
Consecutive numbers are in A.P. and sum for such a set = number of terms * (first term + last term) / 2
If we divide the sum by number of terms then we get average. hence average = (first term + last term) / 2
Set of 5 numbers - a, a+1, a+2, a+3, a+4
Average = (first term + last term) / 2 = (a + a+4) / 2 = a+2
Average = a+2 = n
Set of 7 numbers - a, a+1, a+2, a+3, a+4, a+5, a+6
Average = (first term + last term) / 2 = (a + a+6) / 2 = a+3 = (a+2)+1
Average = n + 1
10 Sep 2017, 08:52
Kudos
Bookmarks
niks18
Consider a sequence of seven consecutive integers. The average of the first five integers is \(n\). The average of all the seven integers is:
A. \(n\)
B. \(n+1\)
C. \(k*n\), where \(k\) is a function of \(n\)
D. \(n+\frac{2}{7}\)
E. \(n+2\)
A. \(n\)
B. \(n+1\)
C. \(k*n\), where \(k\) is a function of \(n\)
D. \(n+\frac{2}{7}\)
E. \(n+2\)
OE
Average of consecutive numbers in an ODD sequence = Middle number of the sequence
Let the seven consecutive integers be \(1,2,3,4,5,6,7\). Hence average of this sequence \(= 4\)
First five integers of the above sequence are \(1,2,3,4,5\). Average of this sequence \(= 3 = n\)
Clearly, \(4 = 3 +1 = n+1\)
Hence Option B
