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Consider the three points in the x-y plane: P = (8, 4), Q = (6, 7), an
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23 Oct 2018, 03:04
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Difficulty:
55% (hard)
Question Stats:
57% (01:31) correct 43% (01:21) wrong based on 82 sessions
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Consider the three points in the x-y plane: P = (8, 4), Q = (6, 7), and R = (9, 0). Rank these three points from closest to the origin, (0, 0), to furthest from the origin.
A. P, Q, R B. P, R, Q C. Q, P, R D. R, P, Q E. R, Q, P
Consider the three points in the x-y plane: P = (8, 4), Q = (6, 7), an
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23 Oct 2018, 03:40
2
Bunuel wrote:
Consider the three points in the x-y plane: P = (8, 4), Q = (6, 7), and R = (9, 0). Rank these three points from closest to the origin, (0, 0), to furthest from the origin.
A. P, Q, R B. P, R, Q C. Q, P, R D. R, P, Q E. R, Q, P
Distance between any two points \((x_1, y_1)\)and \((x_2, y_2)\) \(= √[(x_2-x_1)^2 + (y_2-y_1)^2]\)
Distance of P from Origin, OP \(= √(8^2+4^2 = √80\)
Distance of Q from Origin, OP \(= √(6^2+7^2 = √85\)
Distance of R from Origin, OP \(= √(9^2+0^2 = √81\)
Answer: Option B
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Consider the three points in the x-y plane: P = (8, 4), Q = (6, 7), an
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23 Oct 2018, 05:44
GMATinsight wrote:
Bunuel wrote:
Consider the three points in the x-y plane: P = (8, 4), Q = (6, 7), and R = (9, 0). Rank these three points from closest to the origin, (0, 0), to furthest from the origin.
A. P, Q, R B. P, R, Q C. Q, P, R D. R, P, Q E. R, Q, P
Distance between any two points \((x_1, y_1)\)and \((x_2, y_2)\) \(= √[(x_2-x_1)^2 + (y_2-y_1)^2]\)
Distance of P from Origin, OP \(= √(8^2+4^2 = √80\)
Distance of Q from Origin, OP \(= √(6^2+7^2 = √85\)
Distance of R from Origin, OP \(= √(9^2+0^2 = √81\)
Answer: Option B
GMATinsight but this formula \(√[(x_2-x_1)^2 + (y_2-y_1)^2]\) includes \(x_1\) and \(x_2\) and \(y_1\) and \(y_2\), whereas we have only P = (8, 4) i.e. \(x_1\)and \(y_1\) can you please explain this phenomen ?
Re: Consider the three points in the x-y plane: P = (8, 4), Q = (6, 7), an
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23 Oct 2018, 05:48
1
dave13 wrote:
GMATinsight wrote:
Bunuel wrote:
Consider the three points in the x-y plane: P = (8, 4), Q = (6, 7), and R = (9, 0). Rank these three points from closest to the origin, (0, 0), to furthest from the origin.
A. P, Q, R B. P, R, Q C. Q, P, R D. R, P, Q E. R, Q, P
Distance between any two points \((x_1, y_1)\)and \((x_2, y_2)\) \(= √[(x_2-x_1)^2 + (y_2-y_1)^2]\)
Distance of P from Origin, OP \(= √(8^2+4^2 = √80\)
Distance of Q from Origin, OP \(= √(6^2+7^2 = √85\)
Distance of R from Origin, OP \(= √(9^2+0^2 = √81\)
Answer: Option B
GMATinsight but this formula \(√[(x_2-x_1)^2 + (y_2-y_1)^2]\) includes \(x_1\) and \(x_2\) and \(y_1\) and \(y_2\), whereas we have only P = (8, 4) i.e. \(x_1\)and \(y_1\) can you please explain this phenomen ?
When we calculate length of OP then \((x_1, y_1)\) = \((8, 5)\) and \((x_2, y_2)\) = \((0, 0)\)
i.e. OP = \(= √[(8-0)^2+(4-0)^2] = √(8^2+4^2) =√80\)
I hope this helps
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57% (01:31) correct 
