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13 Dec 2024, 10:46
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (00:24) correct
28% (01:02) wrong based on 14 sessions
History
Date
Time
Result
Not Attempted Yet
Cost is expressed by the formula \(tb^4\). If b is doubled, by what factor has the cost increased?
(A) 2
(B) 6
(C) 8
(D) 16
(E) \(\frac{1}{2}\)
(A) 2
(B) 6
(C) 8
(D) 16
(E) \(\frac{1}{2}\)
13 Dec 2024, 11:48
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C = t(b^4)
Now b is doubled so it becomes 2b
New C = t (2b)^4
= t*16*(b^4)
= 16t(b^4)
= 16C
So 16 times
Now b is doubled so it becomes 2b
New C = t (2b)^4
= t*16*(b^4)
= 16t(b^4)
= 16C
So 16 times
28 Feb 2025, 12:32
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OE
Pick numbers to see what happens to the cost when b is doubled. If the original value of b is 2, the cost is 16t. When b is doubled to 4, the new cost value is 256t. The cost has increased by a factor of 256/16, or 16.
Pick numbers to see what happens to the cost when b is doubled. If the original value of b is 2, the cost is 16t. When b is doubled to 4, the new cost value is 256t. The cost has increased by a factor of 256/16, or 16.
