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16 May 2007, 00:47
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Could you try the problem below? Please, explain your answer.
S20-Q22. The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of
Parkdale.
The argument above is flawed because it fails to take into account
A. changes in the population density of both Parkdale and Meadowbrook over the past four years
B. how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale
C. the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale
D. the violent crime rates in Meadowbrook and Parkdale four years ago
E. how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures
S20-Q22. The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of
Parkdale.
The argument above is flawed because it fails to take into account
A. changes in the population density of both Parkdale and Meadowbrook over the past four years
B. how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale
C. the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale
D. the violent crime rates in Meadowbrook and Parkdale four years ago
E. how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures
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16 May 2007, 02:52
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not too sure, but I think it is (A)
A. changes in the population density of both Parkdale and Meadowbrook over the past four years
yes, the density could explain the difference.
B. how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale
violent crime does not depend on population rate, since it is defined per 1,000 people.
C. the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale
out of scope, it is about violent crimes!
D. the violent crime rates in Meadowbrook and Parkdale four years ago
we know from the passage
E. how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures
out of scope!
A. changes in the population density of both Parkdale and Meadowbrook over the past four years
yes, the density could explain the difference.
B. how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale
violent crime does not depend on population rate, since it is defined per 1,000 people.
C. the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale
out of scope, it is about violent crimes!
D. the violent crime rates in Meadowbrook and Parkdale four years ago
we know from the passage
E. how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures
out of scope!
I'll go with (D).
The question just tells us wat is the % increase.
Let's say the the orignal rates were
M - 1%
a 60% rise will make it to 1.6%
whereas for
P - 2%
a 10% rise will make it 2.2%
so the argument is flawed
Quote:
The question just tells us wat is the % increase.
Let's say the the orignal rates were
M - 1%
a 60% rise will make it to 1.6%
whereas for
P - 2%
a 10% rise will make it 2.2%
so the argument is flawed
