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# Crown throws 3 dice and records the product of the numbers

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VP
Joined: 18 Nov 2004
Posts: 1399
Crown throws 3 dice and records the product of the numbers  [#permalink]

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14 Mar 2005, 22:12
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1. Crown throws 3 dice and records the product of the numbers appearing at the top of each die as the result of the attempt. What is the probability that the result of any attempt is an odd integer divisible by 25?

A) 7/216
B) 5/91
C) 13/88
D) 1/5
E 3/8

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VP
Joined: 13 Jun 2004
Posts: 1094
Location: London, UK
Schools: Tuck'08

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14 Mar 2005, 22:33
1
A for me : 7/216

maximum number with 3 dices : 6*6*6 = 216
maximum integer divisible by 25 : 5*5*6 = 150

odd integer divisible by 25 and <=150 : 25, 75, 125

25 -> 5*5*1, 5*1*5, 1*5*5
75 -> 5*5*3, 5*3*5, 3*5*5
125 -> 5*5*5

total : 7 possibilities
total potential outcome : 216

7/216
Manager
Joined: 25 Oct 2004
Posts: 236

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15 Mar 2005, 08:10
7/216

25,75,125

25=1*5*5===>> in 3! ways
75= 5*5*3===>> in 3! ways
125= 5*5*5===>> in 1 way

so total ways = 6+6+1

probability= 7/6*6*6
=7/216
Manager
Joined: 11 Jan 2005
Posts: 55
Location: Mexico City

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15 Mar 2005, 08:54
I got 7/216 too but it took me a while.

anybody have a better method than the longer way of finding diff combinations and counting them up. is there a formula i am missing?
Intern
Joined: 31 Jan 2005
Posts: 1

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17 Mar 2005, 04:52
The total potential outcomes are not 216 :

as you can see , the product 6 * 6 * 6 = 216 but

6*6*5 = 180

then we have : 5*5*6 = 150

and then : 4*6*6 =144

We must consider that in order to calculate the "space of events" we have to pick only the possible products of our numbers .

So , imho , OA could be 5/91 .

Regards
Manager
Joined: 01 Feb 2005
Posts: 57
Location: NYC

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17 Mar 2005, 18:37
babar wrote:
The total potential outcomes are not 216 :

as you can see , the product 6 * 6 * 6 = 216 but

6*6*5 = 180

then we have : 5*5*6 = 150

and then : 4*6*6 =144

We must consider that in order to calculate the "space of events" we have to pick only the possible products of our numbers .

So , imho , OA could be 5/91 .

Regards

Why do we have to pick only 'possible products of our numbers'??
Manager
Joined: 06 Oct 2004
Posts: 57

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18 Mar 2005, 16:21
i did not understand how the total potential outcome would be 216
Can anyone pls explain!!!
I think we cannot take all the nos upto 216...right????
Manager
Joined: 04 Mar 2005
Posts: 102
Location: NYC

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18 Mar 2005, 20:11
Total number of outcomes = 6 *6*6
-> 6 outcomes for dice1 * 6 outcomes for dice2 * 6outcomes for dice3
=> 6*6*6 = 216

--== Message from the GMAT Club Team ==--

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This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Non-Human User
Joined: 09 Sep 2013
Posts: 8096
Re: Crown throws 3 dice and records the product of the numbers  [#permalink]

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05 Jul 2018, 07:37
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Crown throws 3 dice and records the product of the numbers &nbs [#permalink] 05 Jul 2018, 07:37
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