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Thelionking1234
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catfreak
Experts, one clarification - If I modify the question little bit and let the new dimensions be 16* 20 * 16
then we can obviously place 20 cylinders as above on the 16*20 base.
Now, there will be 4 inches left in the height of the cuboid and we can place more cylinders in horizontal position over the vertical ones.

Please clarify that shall we consider these extra ones - y/n

Considering a Base of 20, hight of 16 and width of 14. It is possible to put cans vertically , you will have room for 15 and then you can just put 5 horizontally on top. And it still 20 the max number of cans
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Bunuel need help with a similar problem in the forum where the height is also being taken into consideration:
What is the maximum number of cylinders of height 6 and radius 3 that can fit into an empty box with interior dimensions 12 x 18 x 20?
A. 120
B. 25
C. 18
D. 12
E. 6

Can you please explain what I could be missing here?
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BLM
Bunuel need help with a similar problem in the forum where the height is also being taken into consideration:
What is the maximum number of cylinders of height 6 and radius 3 that can fit into an empty box with interior dimensions 12 x 18 x 20?
A. 120
B. 25
C. 18
D. 12
E. 6

Can you please explain what I could be missing here?

That question is discussed here: https://gmatclub.com/forum/what-is-the- ... 75650.html
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