d^d = 2^p d = 2^64 p =

Question

d^d = 2^p

d = 2^64

p = ?

giddi77 · Answer

Is it 2^70?

(a^b)^c = a^(bc)

d^d = 2^(64*2^64) = 2^(2^6*2^64) = 2^(2^70)

=> p = 2^70

thearch · Answer

2^64^((2)^64) is 2^(64*64*2)=2^8192 it's a bit big... :roll:

giddi77 · Answer

thearch,

(a^b)^c = a^(bc)

a = 2
b = 64
c = 2^64
For simplification just ignore the base a and focus on b*c

b*c = 64*2^64 = 2^6*2^64 = 2^(6+64) = 2^70

HTH

giddi77 · Answer

Isn't it the same?

(a^b)^c^c = a^(b*c^c)

but ((a^b)^c)^c) = a^(b*c*c) = a^(b*c^2)

This is what I remember from high school algebra, I will verify and update the post if this is wrong.

kook44 · Answer

https://img134.imageshack.us/img134/3614/2006040210529iz.gif 

therefore, p=2^70

razrulz · Answer

how did u use the power..? i mean carry a ^ 2 like the way we write?

TeHCM · Answer

OA is 2^70

I forgot this rule for exponents....tks

bumpbot · Answer

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d^d = 2^p d = 2^64 p =

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