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Hi,

I have done with below approach and is quicker-

let m/n=x

x=0.3636363636363636........................... Eq.1

Now multiply it by 100 (why?: cause two numbers are repeating again and again)

100x= 36.36363636363636...................... Eq.2


Now, Eq.2 - Eq.1

99x=36

x=36/99

x=4/11

Now, there you have m as 4 or its multiplier.

Minimum have to be "4".

In case 3 number were repeating again and again then we have multiply by 1000. (here, intention of doing this is to remove repeating part of number so that we can an integer to work with).
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