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Bunnel Is there any Property that if a number Q is not Divisible by 5 then Q!(factorial) is also not divisible by 5??

Ex: If Q = 14 not Divisible by 5, then 14! ( 14x13x12....1) Can't we consider that 10 ,5 are in the factorial list so 14! can be divisible.
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I welcome analysis on my posts and kudo +1 if helpful. It helps me to improve my craft.Thank you

I don't agree with the explanation. for a number to be divisible by 9, it is mandatory that sum of all its digits adds up to 9. Here we have the number as 1234X. So the sum of existing digits is 1+2+3+4=1, hence X can be 8 for the number to be divisible by 9. Hence the explanation for statement b is not true.

I don't agree with the explanation. for a number to be divisible by 9, it is mandatory that sum of all its digits adds up to 9. Here we have the number as 1234X. So the sum of existing digits is 1+2+3+4=1, hence X can be 8 for the number to be divisible by 9. Hence the explanation for statement b is not true.

Please read carefully. (2) says that @ is divisible by 9 not N.
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I think this is a poor-quality question and I don't agree with the explanation. (2) @@ is divisible by 9. can be 0 or 9 (note that zero is divisible by every integer except zero itself). Not sufficient. So it could be 12340 or 12349 but these are not divisible by 9. It should be 12348, because the sum of 1+2+3+4+8 is divisible by 9.

I think this is a poor-quality question and I don't agree with the explanation. (2) @@ is divisible by 9. can be 0 or 9 (note that zero is divisible by every integer except zero itself). Not sufficient. So it could be 12340 or 12349 but these are not divisible by 9. It should be 12348, because the sum of 1+2+3+4+8 is divisible by 9.

The question is fine. You just did not read it carefully: (2) says that the units digit, @, is divisible by 9, not the number itself. _________________
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