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08 Jun 2026, 03:54
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I like the solution - it’s helpful.
29 Jun 2026, 07:22
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Key point is speeds of the two objects are the same
Lets say there are two A and B which have speeds of A (speeds are same)
Now since they are meeting at p in 2 hour it means that D / 2A = 2 i.e D = 4A ....i
Now since one bus is travelling for 1 hour alone (let that be bus A). So the revised time to meet would be (D - A) / 2A i.e 1.5hours
*** Now we know that the bus A reached P in 2 hours, hence in 1 hour it has covered half way to P, from there if the meeting time is 1.5 hours it means that for the gap of 24 miles the bus is took only 0.5 hours.
Hence speed of A is 24/0.5 which is 48 miles per hour ---> Plug this in ii you get 4 x 48 which is 192
Lets say there are two A and B which have speeds of A (speeds are same)
Now since they are meeting at p in 2 hour it means that D / 2A = 2 i.e D = 4A ....i
Now since one bus is travelling for 1 hour alone (let that be bus A). So the revised time to meet would be (D - A) / 2A i.e 1.5hours
*** Now we know that the bus A reached P in 2 hours, hence in 1 hour it has covered half way to P, from there if the meeting time is 1.5 hours it means that for the gap of 24 miles the bus is took only 0.5 hours.
Hence speed of A is 24/0.5 which is 48 miles per hour ---> Plug this in ii you get 4 x 48 which is 192
