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D01-38

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Re: D01-38  [#permalink]

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New post 03 Jun 2019, 05:13
I don't know if this is the correct approach (moderators please point out if it's not) but the question states that there are 3 samples (s1, s2 and s3) and their are 3 cups in each sample (c1, c2, c3). Probability= Favourable/Total and total is 9C4= 126. As for favourable we need to determine the contestant is not tasting all samples, which means they will only choose from two samples which Is 6C4=15. Since this can be done in 3 ways our favourable is 15*3=45 which means probability= 45/126= 5/14.
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Re: D01-38   [#permalink] 03 Jun 2019, 05:13

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