Data Sufficiency Competition--Prizes can be won

C it is
The distance between two days with the same number of the neighbouring months must be 28 or 29 or 30 or 31 days

(1) alone
His birthday fell in Sunday and in the previous month of the same year, the day of the month on which he was born fell on a Thursday so the distance betwwen these two days must be 31 days. This means that the previous month of the one in which Yezz was born must has 31 days.
(2) alone
Also tell that the distance between his birthday and the day of the month on which he was born in the next month of the same year must be 31 days.
This means that the month in which he was born must has 31 days.
(1)or (2) alone tells us nothing but (1) (2) together conclude that Yezz was born in August. Because there are just neighbouring months of July and August which both have 31 days and
stay in the same year.

Yes, that's the right answer..................

I have sent the link to the file.........

Keep rocking........................

My Bad......i missed being the first to solve A DS in my name ....... Ciceron u should ve PM'd me ........quangviet512 brilliant answer

Thanks To Ciceron i became one of GMAT club Immortals

Hey yezz, don't worry u r going to get many chances............

3 DAYS IT IS ( 6 CATS 6 RATS IN THE SAME THREE DAYS )

yes, that's the answer............

What abt the first one..........

man am joking ...low traffic on the forum today so i am trying keep it up ( mind allert)

All barbers

All barbers

Yezz, u have to think about the above answer once again..............

Fine, here comes our next question...................

8. In how many days is the work completed by A and B if they work on alternate days?

1: A alone can do the work in 12 days.
2: B alone can do the work in 15 days.

This is quite simple one.................So, don't ask for a prize........

ST 1 is not suff
st 2 is not suff

Combining we can get the amt of work done in 2 days..thus we can find the required answer..

So my answer is C

should be 120/9 (13,3 days)
if they work simultaneously it'd be 15*12/27 or 60/9 since it's alternate we double the amount of days

Not satisfied.............
Check it again

Answer would be C
st 1 is insuf
st2 is insuff

Combining 1 and 2 seems suff but is not.. It does not hold true for the following ex

Consider a can finish the work in 3 days so in one day he finishes 1/3
Consider that b can finish the work in 2 days so in one day it finishes 1/2
Now a has to finish remaning 1/6 of the work that would require him half a day so total comes to 2.5
Similarly if we solve for A and B for given values we should be able to reach an answer.

Please correct if I am wrong?

Regards
Yogesh