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07 Dec 2021, 04:15
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B
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Difficulty:
95%
(hard)
Question Stats:
56% (02:49) correct
44%
(02:50)
wrong
based on 110
sessions
History
Date
Time
Result
Not Attempted Yet
David and Michael together can finish a job in 4 days 19 hours 12 minutes. If David works at two-thirds Michel's speed, how long does it make Michael alone to finish the same job?
A. 6 days
B. 8 days
C. 10 days
D. 12 days
E. 13 days
Are You Up For the Challenge: 700 Level Questions
A. 6 days
B. 8 days
C. 10 days
D. 12 days
E. 13 days
Are You Up For the Challenge: 700 Level Questions
16 Jun 2025, 06:22
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Method: Using efficiency
Michael's rate of work be \(x\), and David's be \(\dfrac{2}{3}x \). Therefore, working together their rate of work is, \(x + \dfrac{2}{3}(x) = \dfrac{5}{3}(x)\)
They completed a job in \(4\) d \(19\) h and \(12\) m, converting in hours, i.e., \(4\)d = \(96\)h, \(12\) min \(= \dfrac{12}{60}\) h. Time \(= 96+19 + 0.2 = 115.2\) h.
So, \(\dfrac{1}{\left(\dfrac{5}{3}\right) \cdot x} = 115.2 \Longrightarrow x = \dfrac{1}{192}\) h.
Thus Michael alone takes, \(\dfrac{1}{m} = 192 h = \dfrac{192}{24} = 8\) d
ANS B
Michael's rate of work be \(x\), and David's be \(\dfrac{2}{3}x \). Therefore, working together their rate of work is, \(x + \dfrac{2}{3}(x) = \dfrac{5}{3}(x)\)
They completed a job in \(4\) d \(19\) h and \(12\) m, converting in hours, i.e., \(4\)d = \(96\)h, \(12\) min \(= \dfrac{12}{60}\) h. Time \(= 96+19 + 0.2 = 115.2\) h.
So, \(\dfrac{1}{\left(\dfrac{5}{3}\right) \cdot x} = 115.2 \Longrightarrow x = \dfrac{1}{192}\) h.
Thus Michael alone takes, \(\dfrac{1}{m} = 192 h = \dfrac{192}{24} = 8\) d
ANS B
02 Jul 2025, 04:06
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Bunuel just wanted to understand why this question is categorised as 805+ is it due to the time spent converting days to hours and minutes or is this generally how difficult a work and time question can get on the GMAT?
